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ella [17]
2 years ago
5

What is the force the when does when Gravity pushes you​

Physics
2 answers:
BARSIC [14]2 years ago
6 0

Answer:

Image result for what is the force the when does when Gravity pushes you​

The important thing to remember is that gravity is neither a push nor a pull; what we interpret as a “force” or the acceleration due to gravity is actually the curvature of space and time — the path itself stoops downward.

Explanation:

Image result for what is the force the when does when Gravity pushes you​

The important thing to remember is that gravity is neither a push nor a pull; what we interpret as a “force” or the acceleration due to gravity is actually the curvature of space and time — the path itself stoops downward.

Nezavi [6.7K]2 years ago
5 0

Answer:

It is called gravitational force.

Explanation:

{ \boxed{ \rm{F =  \frac{GM_{a} m _{a}}{ {r}^{2} } }}}

  • F is the gravitational force
  • Ma is the mass of a planetary body
  • ma is mass lf body being attracted
  • r is the separation distance
  • G is the universal gravitational constant

→ Assume you are in space and you have a mass of ma, and you are r metres from the Earth of mass Ma. The force F will be experienced and you will tend to be pulled towards the Earth when you are in its gravitational field.

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Photons of wavelength 65.0 pm are Compton-scattered from a free electron which picks up a kinetic energy of 0.75 keV from the co
DIA [1.3K]

0.6764*10^-10m

Explanation:

Using E= hc/wavelength

(4.14x10^-15)x(3.0x10^8)/(65x10^-12)=0.1911x10^5 eV=19.1 keV

So subtract the calculated energy from the given energy of scattered photons

9.11-0.75=18.36 keV

To find wavelength

Wavelength= hc/ E

[(4.14x 10^-15)x (3.0x10^8)]/(18.36*10^3) =0.6764^-10 m

8 0
3 years ago
oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student
pochemuha

Answer:

m = 63 grams

Explanation:

ω = 10 cycles/s(2π radians/cycle) = 20π rad/s

ω = √(k/m)

m = k/ω² = 250/(20π)² = 0.06332... kg

6 0
3 years ago
What is the changing of the position of an object relative to a point of reference
Bond [772]
The displacement ........................
5 0
3 years ago
Which equation describes the sum of the vectors plotted below?
bearhunter [10]

Equation C describes the sum of the vectors plotted below.

<h3>What is a vector?</h3>

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

If no vector can be written as a linear combination of the others, a set of vectors is said to be linearly independent.

The given points from the graph is obtained as;

a = (2,1)

b = (3,-2)

Vector, OA = 2x + y

Vector, AB = x - 3 y

From the triangular lawe of the vector addition;

\rm r=  \vec{OA} +\vec{OB}\\\\\ r= 2x+y+x-3y \\\\ r= 3x-2y

Hence,option C is correct.

To learn more about the vector refer to the link;

brainly.com/question/13322477

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8 0
1 year ago
Calculate the force of gravity on the 0.60- kg mass if it were 1.3×107 m above Earth's surface (that is, if it were three Earth
nignag [31]
The gravitational force between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation

In this problem, the first object has a mass of m_1=0.60 kg, while the second "object" is the Earth, with mass m_2=5.97 \cdot 10^{24}kg. The distance of the object from the Earth's center is r=1.3 \cdot 10^7 m; if we substitute these numbers into the equation, we find the force of gravity exerted by the Earth on the mass of 0.60 kg:
F=G \frac{m_1m_2}{r^2}=(6.67\cdot 10^{-11}) \frac{(0.60 kg)(5.97 \cdot 10^{24} kg)}{(1.3 \cdot 10^7 m)^2}=  1.41 N
5 0
3 years ago
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