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ella [17]
3 years ago
5

What is the force the when does when Gravity pushes you​

Physics
2 answers:
BARSIC [14]3 years ago
6 0

Answer:

Image result for what is the force the when does when Gravity pushes you​

The important thing to remember is that gravity is neither a push nor a pull; what we interpret as a “force” or the acceleration due to gravity is actually the curvature of space and time — the path itself stoops downward.

Explanation:

Image result for what is the force the when does when Gravity pushes you​

The important thing to remember is that gravity is neither a push nor a pull; what we interpret as a “force” or the acceleration due to gravity is actually the curvature of space and time — the path itself stoops downward.

Nezavi [6.7K]3 years ago
5 0

Answer:

It is called gravitational force.

Explanation:

{ \boxed{ \rm{F =  \frac{GM_{a} m _{a}}{ {r}^{2} } }}}

  • F is the gravitational force
  • Ma is the mass of a planetary body
  • ma is mass lf body being attracted
  • r is the separation distance
  • G is the universal gravitational constant

→ Assume you are in space and you have a mass of ma, and you are r metres from the Earth of mass Ma. The force F will be experienced and you will tend to be pulled towards the Earth when you are in its gravitational field.

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Given one mole of diamond vs one mole of graphite,
grandymaker [24]

Answer:

The pressure is P= -  6.39*10^8Pa

The temperature is T =1218.63 K

Explanation:

Generally Gibbs free energy is mathematically represented as

                   G = E + PV -TS

   Where  E is the enthalpy

               PV is the pressure volume energy (i.e PV energy)

                S  is the entropy

                T is the temperature

For stability to occur the Gibbs free energy must be equal to zero

Considering Diamond

  So at temperature of  T = 300 K

         E + PV - TS = 0

making P the subject

          P = \frac{TS-E}{V}

Now substituting 300 K for T , 2900 J  for E ,

                              3.42cm^3 = \frac{3.42}{1*10^6} = 3.42*10^{-6}m^3 for V and 2.38 J/K for S

     P = \frac{(300 * 2.38)- 2900}{3.42*10^{-6}}

         P= -  6.39*10^8Pa

The negative sign signifies the direction of the pressure

Given that  P = 1*0^5Pa

making T the subject

            T = \frac{PV+E}{S}

Substituting into the equation

            T = \frac{1*10^5 * 3.42 *10^{-6}+2900}{2.38}

                T =1218.63 K

             

         

7 0
3 years ago
Read 2 more answers
A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains
Colt1911 [192]

If only I was smart then I could help you :/ no but like for real im madddd dumb sorry :(

4 0
4 years ago
Two objects are in freefall. Object A experiences a gravitational force of
Vlad1618 [11]

<u>Answer:</u>

Both the objects A and B will have the same acceleration.

<u>Explanation :</u>

The objects will have the same acceleration as both are under free fall condition. When objects are under the free fall condition, the only force that acts on the object is its weight.

Weight is the force acting on a body of some mass, and the formula for finding the weight of a body is- Weight = mass × acceleration due to gravity(g).

Therefore, here the different weight is due to the difference masses of both bodies, and not due to the different acceleration values.

3 0
3 years ago
how much time would it take for the sound of a thunder to travel 1,500 meters if sound travelers at a speed of 330 m/sec?
inysia [295]

(1,500 meters) x (1 sec/330 meters) =

(1,500 / 330) (meters-sec/meters) =

4.55 seconds

8 0
3 years ago
1. A toy car with mass m1 travels to the right on a frictionless track with a speed of 3 m/s. A second toy car with mass m2 trav
Alika [10]

Answer:

v = 3(m1 - 2m2)/(m1 + m2)

Explanation:

Parameters given:

Velocity of first toy car with mass m1, u1 = 3 m/s (taking the right direction as the positive axis)

Velocity of second toy car with mass m2, u2 = -6 m/s (taking the left direction as the negative x axis)

Using conservation of momentum principle:

Total initial momentum = Total final momentum

m1*u1 + m2*u2 = m1*v1 + m2*v2

Since they stick together after collision, they have the same final velocity.

m1*3 + (m2 * -6) = m1*v + m2*v

3m1 - 6m2 = (m1 + m2)v

v = (3m1 - 6m2) / (m1 + m2)

v = 3(m1 - 2m2) / (m1 + m2)

8 0
3 years ago
Read 2 more answers
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