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Bond [772]
3 years ago
5

HELP PLEASE . im in credit recovery bc i obviously suck at math im going to post a photo with the question & answers .someon

e pls answer this for me .

Mathematics
1 answer:
Lostsunrise [7]3 years ago
7 0
Girl im on the same boat as you 
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Serjik [45]

Answer:

here question was not clear

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Please help.<br> Its a True or False question.
faust18 [17]

Answer:

1. False

2. True

3. True

Step-by-step explanation:

Remark

The point of this question is to encourage you to make use of your calculator. Every calculator can find square roots as far as I know.

Givens

\sqrt{70} = 8.367

\sqrt{72} = 8.49

\sqrt{77} = 8.77

One

Point A is roughly 8.15. The square root of 70 is over 8.3 So square root 70 is to the right of point A. False.

Two

Square root 72 is 8.49. B is 8.3 and C is 8.6. The statement is True

Three

sqrt(77) = 8.77. Point D is 8.75.  The answer is true, but I wouldn't want to bet money on it. The difference is slightly less than 2 100s.

4 0
3 years ago
Read 2 more answers
Solve the equation<br> 12 + 4m = 24<br> A)m=9<br> B)m=8<br> C)m=3<br> D)m=-6
pantera1 [17]
12 +4m = 24

4m = 12

m = 12/4

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8 0
3 years ago
? is in the picture plsss answer
balandron [24]

Answer:

You have a triangle and a Square!

Step-by-step explanation:

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3 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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