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Dimas [21]
3 years ago
5

1. Alicia had $-11 in her checking account. She did a few chores and made $44.50. She

Mathematics
1 answer:
Masteriza [31]3 years ago
6 0

Answer:

The answer is 21

Step-by-step explanation:

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If gk=30 what are gh and jk?
Citrus2011 [14]
Not enough information is given
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3 years ago
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Elliot spent $16.15 on ground beef at a grocery store. He purchased 3 and 2 over 5 pounds of ground beef. What is the price per
Andrej [43]

We want to know how much is the price per pound (or unit rate) of ground beef, given that we know the price for Elliot's purchase. We will see that each pound costs $4.75

So we know that (3 + 2/5) lb of ground beef costs $16.15, the cost of a single pound will be given by the quotient between the total cost and the amount purchased, then we need to solve:

P =\frac{ \$ 16.15}{(3 + 2/5)lb}

We can rewrite the denominator as:

(3 + 2/5)lb = (15/5 + 2/5)lb = (17/5) lb

Replacing that we get:

P =\frac{ \$ 16.15}{(17/5)lb} = \frac{ \$ 16.15*5}{17lb} = \$4.75   \ per  \ lb

So each pound of ground beef costs $4.75

If you want to learn more about unit rates, you can read:

brainly.com/question/2375289

4 0
2 years ago
Find the missing side length of the right triangle below. Round your answer to the nearest tenth.
ikadub [295]

Answer:

24.4

Step-by-step explanation:

14² + 20² = c²

196 + 400 =  596

√596 = 24.4

3 0
3 years ago
What is the slope of the lime shown below (6,6)and 1,-4)
Ne4ueva [31]
Slope=
\frac{y2 - y1}{x2 - x1}  =  \frac{6 - ( - 4)}{6 - 1}  =  \frac{10}{5}  = 2
3 0
3 years ago
Solve the following system by substitution -3x+y=-5 and 3x+6y=0
Jobisdone [24]

Answer:

x=\frac{10}{7},\:y=-\frac{5}{7}

Step-by-step explanation:

\begin{bmatrix}-3x+y=-5\\ 3x+6y=0\end{bmatrix}\\\\\mathrm{Isolate}\:x\:\mathrm{for}\:-3x+y=-5:\quad x=-\frac{-5-y}{3}\\\\\mathrm{Subsititute\:}x=-\frac{-5-y}{3}\\\\\begin{bmatrix}3\left(-\frac{-5-y}{3}\right)+6y=0\end{bmatrix}\\\\Simplify\\\\\begin{bmatrix}5+7y=0\end{bmatrix}\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:5+7y=0:\quad y=-\frac{5}{7}\\\\\mathrm{For\:}x=-\frac{-5-y}{3}\\\\\mathrm{Subsititute\:}y=-\frac{5}{7}\\\\x=-\frac{-5-\left(-\frac{5}{7}\right)}{3}

-\frac{-5-\left(-\frac{5}{7}\right)}{3}=\frac{10}{7}\\\\x=\frac{10}{7},\:y=-\frac{5}{7}\\\\

3 0
3 years ago
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