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Travka [436]
3 years ago
8

3m-7=8 solve please NEED HELP

Mathematics
2 answers:
Lapatulllka [165]3 years ago
7 0

Solve for m.

Add 7 to both sides to get 3m=15

Then divide by sides by 3 to get m=5.

The final answer is m=5.

Lilit [14]3 years ago
6 0
1.) add 7 to both sides

3m = 8 + 7

2.) add 8+7

3m = 15

3.) divide both sides by 3

m = 15/3

4.) divide 15/3

5.) m = 5
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8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
2 years ago
8 fewer than the sum of 14 and a number?
Julli [10]
A. Your not multiplying 8 by anything to get this answer your taking 8-14-a
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Here is how to work the problems and write the expressions.

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