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4 years ago

Part B

Physics

1 answer:

dimaraw [331]4 years ago

8 0

At the left side of the reaction

Explanation:

the reaction is spontaneous

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Answer the question please

kirill [66]

Answer:

i think is third

Explanation:

7 0

4 years ago

A uniform rod of mass M and length L can pivot freely at one end. Initially, the rod is oriented vertically above the pivot, in

Leya [2.2K]

Answer:

The speed of its center of mass = $\sqrt{\frac{3}{2}gL}$

Explanation:

Consider the potential energy at the level of center of mass of rod below the pivot=0

Mass of uniform rod=M

Length of rod=L

The rotational inertia about the end of a uniform rod= $\frac{1}{3}ML^2$

Kinetic energy at the level of center of mass of rod below the pivot= $\frac{1}{2}I\omega^2$

Kinetic energy at the level of center of mass of rod above the pivot=0

Potential energy at the level of center of mass of rod above the pivot=mgh

We have to find the center of mass ( in terms of g and L).

According to conservation of law of energy

Initial P.E+Initial K.E=Final P.E+Final K.E

$mgh+0=0+\frac{1}{2} I\omega^2$

Where $K.E=\frac{1}{2} I\omega^2$

I=Moment of inertia

$\omega$ =Angular velocity

Substitute the values then we get

$MgL=\frac{1}{2}\times \frac{1}{3}ML^2\omega^2$

$\omega^2=\frac{6g}{L}$

Now, we know that $\omega=\frac{v}{r}$ , $r=\frac{L}{2}$

Substitute the values then we get

$\frac{v^2}{(\frac{L}{2})^2}=\frac{6g}{L}$

$\frac{v^24}{L^2}=\frac{6g}{L}$

$v^2=\frac{6g\times L^2}{4L}$

$v^2=\frac{3gL}{2}$

$v=\sqrt{\frac{3}{2}gL}$

Hence, the speed of its center of mass = $\sqrt{\frac{3}{2}gL}$

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4 years ago

If the pendulum is taken into the orbiting space station what will happen to the bob? if the pendulum is taken into the orbiting

mezya [45]

Check the attached file for the answer.

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4 years ago

A boat sails south with the help of a wind blowing in the direction s36°e with magnitude 300 lb. find the work done by the wind

olga nikolaevna [1]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
<span>Work=effective force x distance = 300cos36. 100 ft.lb.</span>

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3 years ago

Which of these reactions is responsible for energy radiating from stars, including the Sun?

snow_tiger [21]

Answer: nuclear fusion

Explanation: give me a brainliest

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3 years ago