We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.
We know that formula for permutations is given as
On substituting the given values in the formula we get,
Therefore, there are 39270 ways in which prizes can be awarded.
The probability that the next 4 winners will all be 7th grade students is 3/4
Answer:
x = 2, x = 4
Step-by-step explanation:
The equation y = 10 - 9x is a linear equation and the value of either y or x can be found by substituting the given values of either y or x.
given that y = -8, and substituting this into equation y = 10 - 9x,
we have, -8 = 10 - 9x
10 + 8 = 9x
9x = 18; dividing both sides by 9
x = 2
given that y = -26, and substituting this into equation y = 10 - 9x,
we have, -26 = 10 - 9x
10 + 26 = 9x
9x = 36; dividing both sides by 9
x = 4
Answer:
<2 = 133°
Step-by-step explanation:
< beside <2 = 47
<2 + < beside <2 =180 (straight line)
<2 + 47 =180
<2 = 180-47
<2 = 133°
Answer:
5807259.34663
Step-by-step explanation:
Calculator! Yeah!
Hope this helps!
