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Aleks [24]
2 years ago
12

I have no idea how to do this.

Mathematics
1 answer:
Alex17521 [72]2 years ago
3 0

Answer:

<2 = 133°

Step-by-step explanation:

< beside <2 = 47

<2 + < beside <2 =180 (straight line)

<2 + 47 =180

<2 = 180-47

<2 = 133°

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Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
If the equation below is solved by graphing, which statement is true?
adelina 88 [10]

Answer:

.46

Step-by-step explanation:

If you graph the function, you can see where the two logs intersects. View the image I have attached.

5 0
2 years ago
Read 2 more answers
The quotient of r and 12​
olchik [2.2K]
R/12 is the solution because it is how many times you can put r into 12
4 0
3 years ago
I'm doing homework with a friend and we REALLY need help. What is 650's perfect square if it has one?
creativ13 [48]
It is not a perfect square.
7 0
3 years ago
HELP PLEASE!!Solve the inequality for x. Show each step of the solution. 12x&gt; 9(2x− 3) − 21
JulijaS [17]

Answer:

The answer is x < 8

Step-by-step explanation:

12x > 9(2x− 3) − 21

12x > 18x - 27 - 21

12x > 18x -48

12x - 18x > -48

-6x > -48

6x < 48

x < 48/6

x < 8

7 0
2 years ago
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