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larisa86 [58]
3 years ago
13

A 5.44 kg block initially at rest is pulled to the right along a horizontal, frictionless surface by a constant horizontal force

of 7.4 N. Find the block's speed after it has moved 4.9 m.
Physics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

v = 3.65 m/s

Explanation:

It is given that,

Mass of the block, m = 5.44 kg

Horizontal force acting on the block, F = 7.4 N

We need to find the speed of the block after it has moved 4.9 meters. It can be calculated using the work energy theorem as:

F.d=\dfrac{1}{2}mv^2

v=\sqrt{\dfrac{2Fd}{m}}

v=\sqrt{\dfrac{2\times 7.4\times 4.9}{5.44}}

v = 3.65 m/s

So, the speed of the block is 3.65 m/s. Hence, this is the required solution.

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Which of the following statements is true?
Tresset [83]

Answer:

option A

Explanation:

the correct answer is option A

when the air temperature increases the relative humidity decreases.

When temperature increase the ability to hold water vapor decreases.

higher the water vapor more will be the amount of moisture content.

it take less water vapor to saturate air in a city with low temperature compared with high air temperature.

8 0
4 years ago
Approximating the eye as a single thin lens 2.70 cmcm from the retina, find the focal length of the eye when it is focused on an
Lena [83]

Answer:

0.37 cm

Explanation:

The image is formed on the retina which is at a constant distance of 2.70 cm to the lens. Therefore, image distance = 2.70 cm.

The object is at a distant of 265 cm to the lens of the eye.

From lens formula,

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

where: f is the focal length, u is the object distance and v is the image distance.

Thus, u = 265.00 cm and v = 2.70 cm.

\frac{1}{f} = \frac{1}{265} + \frac{27}{10}

  = \frac{10+7155}{2650}

\frac{1}{f}  = \frac{7165}{2650}

⇒ f = \frac{2650}{7165}

      = 0.37

The focal length of the eye is 0.37 cm.

8 0
3 years ago
Fill in the blank.<br> _______________, not velocity, is used to calculate the average acceleration.
Ainat [17]

Explanation:

Calculating acceleration is complicated if both speed and direction are changing or if you want to know acceleration at any given instant in time. However, it’s relatively easy to calculate average acceleration over a period of time when only speed is changing. Then acceleration is the change in velocity (represented by Δv) divided by the change in time (represented by Δt):

acceleration=ΔvΔt

8 0
3 years ago
Read 2 more answers
Frank has a sample of steel that weighs 80 grams. If the density of his sample of steel is 8 g/cm3, what is the sample’s volume?
olasank [31]
30 is the answer for this

8 0
3 years ago
maize is a monocotyledonous seed and pea is a dicotyledonous seed why? give short and the suitable answer I will mark you as a b
olga nikolaevna [1]

Answer:

A dicot is a flowering plant that has one seed leaves. The monocot plants have a single cotyledon. Maize only has one cotyledon in their seed, so it's a monocot. Seeds having two Cotyles are mainly called a Dicot. A pea is a dicotyledonous plant, the seed (the pea itself) has two halves, cotyledons, hence dicot being 2.

Explanation:

One or more of the cotyledons are the first to appear from a germinating seed. Based on the number of cotyledons, botanists classify flowering plants (angiosperms) into :

a) plants with one embryonic leaf, termed monocotyledonous (monocots).

b) plants with two embryonic leaves, termed dicotyledonous (dicots).

Helpful Link:

https://www.vedantu.com/question-answer/in-pea-caster-and-maize-the-number-of-cotyledons-class-11-biology-cbse-5f626a17e5bde9062ff6d2a3

3 0
3 years ago
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