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marta [7]
3 years ago
13

Does coefficient of linear expansion depends on length​

Physics
1 answer:
nlexa [21]3 years ago
5 0

Answer:

yes

Explanation:

As the formula is α= ΔL/L*ΔT  where alpha (α) is the sign of coefficient of linear expansion

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food product with 10 kg mass is being transported to thesurface of the moon,where the acceleration due to gravity is1.624 m/s2;
larisa [96]

Answer:

In SI units 98.1 N, 16.24 N

English units 22.053861 lbf, 3.6509144 lbf

Explanation:

g = Acceleration due to gravity

m = Mass = 10 kg

Weight on Earth

W=mg\\\Rightarrow W=10\times 9.81\\\Rightarrow W=98.1\ N

Converting to lbf

98.1\times 0.22481=22.053861\ lbf

On Moon

W=10\times 1.624\\\Rightarrow W=16.24\ N

Converting to lbf

16.24\times 0.22481=3.6509144\ lbf

In SI units 98.1 N, 16.24 N

English units 22.053861 lbf, 3.6509144 lbf

5 0
2 years ago
The direction of an electric field is always in the direction _______________ would naturally move.
Masja [62]

Answer:

Im not really sure but Id say weather .

Explanation:

6 0
3 years ago
One problem with weight training as a way to improve overall health is that the results of a weight-training program are not mea
Ede4ka [16]

One problem with weight training as a way to improve overall health is that the results of a weight-training program are not measurable.

B.False

5 0
3 years ago
Read 2 more answers
Part complete How long must a simple pendulum be if it is to make exactly one swing per five seconds?
shtirl [24]

Answer:

L=6.21m

Explanation:

For the simple pendulum problem we need to remember that:

\frac{d^{2}\theta}{dt^{2}}+\frac{g}{L}sin(\theta)=0,

where \theta is the angular position, t is time, g is the gravity, and L is the length of the pendulum. We also need to remember that there is a relationship between the angular frequency and the length of the pendulum:

\omega^{2}=\frac{g}{L},

where \omega is the angular frequency.

There is also an equation that relates the oscillation period and the angular frequeny:

\omega=\frac{2\pi}{T},

where T is the oscillation period. Now, we can easily solve for L:

(\frac{2\pi}{T})^{2}=\frac{g}{L}\\\\L=g(\frac{T}{2\pi})^{2}\\\\L=9.8(\frac{5}{2\pi})^{2}\\\\L=6.21m

3 0
3 years ago
raising the temperature of a gas will increase its pressure If which of the following happens the volume is increased but the nu
Nadusha1986 [10]
D, as the others will result in the likelihood of the particles colliding decreasing

Hope it helps))

3 0
2 years ago
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