Answer:
Heat capacity, Q = 2090 Joules.
Explanation:
Given the following data;
Mass = 100 grams
Specific heat capacity = 4.18 J/g°C.
Temperature = 5°C
To find the quantity of heat required;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
t represents the temperature of an object.
Substituting into the formula, we have;
Heat capacity, Q = 2090 Joules.
Answer:
Explanation:
From the question we are told that
Mass
Velocity of mass
Force of Tunnel
Length of Tunnel
Height of frictional incline
Angle of inclination
Acceleration due to gravity
First Frictional surface has a coefficient
Second Frictional surface has a coefficient
Generally the initial Kinetic energy is mathematically given by
Generally the work done by the Tunnel is mathematically given as
Therefore
Generally the energy lost while climbing is mathematically given as
Generally the energy lost to friction is mathematically given as
Generally the energy left in the form of mass is mathematically given as
Since
Therefore
It slide along the second frictional region