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MaRussiya [10]
3 years ago
12

Im bored who wanna talk on google docs or sum

Chemistry
2 answers:
soldier1979 [14.2K]3 years ago
7 0
Jsjskskskkskskkdnrjdjdjdjjdisksksjjsjdjdjdjjdjsjsjdjdjdj
xeze [42]3 years ago
6 0
Alright let’s do it!!
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ololo11 [35]
4.4x10^18 I think or ya
7 0
3 years ago
Describe how you might determine the m/z and relative abundance of the ions contributing to the peak at 21.876 min
aliya0001 [1]

The m/z and relative abundance of the ions contributed to the peak at 21.876 min. The relative abundance will be 21.876%.

<h3>What is relative abundance?</h3>
  • The proportion of atoms with a particular atomic mass present in an element sample taken from a naturally occurring sample is known as the relative abundance of an isotope.
  • When the relative abundances of an element's isotopes are multiplied by their atomic masses and the results are added up, the result is the element's average atomic mass, which is a weighted average.
  • Chemists often divide the number of atoms in a particular isotope by the sum of the atoms in all the isotopes of that element, then multiply the result by 100 to determine the percent abundance of each isotope in a sample of that element.

To learn more about relative abundance with the given link

brainly.com/question/1594226

#SPJ4

8 0
2 years ago
What can you make with molecules
bagirrra123 [75]

Answer:

H20

Explanation:

H20, is water and this is an example of a molecule.  Molecules are "atoms bonded together." And hydrogen and oxygen are bonded making it a molecule.

6 0
3 years ago
which equation is setup correctly to determine the volume of a 1.5 mol sample of oxygen gas at 22 degrees Celsius and 100 kPa
rjkz [21]
Hello!

We have the following data:


v (volume) = ? (in L)
n (number of mols) = 1,5 mol
T (temperature) = 22 ºC 
First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273,15
TK = 22 + 273,15
TK = 295,15

P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm
R (gas constant) = 0,082 atm.L / mol.K

<span>We apply the data above to the Clapeyron equation (gas equation), let's see:

</span>P*V = n*R*T

0,987*V = 1,5*0,082*295,15

0,987V = 36,30345

V =  \dfrac{36,30345}{0,987}

\boxed{\boxed{V \approx 36,78\:L}} \end{array}}\qquad\checkmark

I hope this helps. =)
4 0
4 years ago
5.0 g of zinc how many moles is this
Alexxandr [17]

Explanation

Given

Mass of zinc = 5.0 g

We know molar mass of Zinc =

8 0
2 years ago
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