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Pachacha [2.7K]
3 years ago
11

What can you make with molecules

Chemistry
1 answer:
bagirrra123 [75]3 years ago
6 0

Answer:

H20

Explanation:

H20, is water and this is an example of a molecule.  Molecules are "atoms bonded together." And hydrogen and oxygen are bonded making it a molecule.

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1. The
rodikova [14]

Answer:

1. Proton = electron if the element is not in an ionic state

proton = atomic number

3 0
3 years ago
uch Activity 2 - Look at Me Directions: Given the illustrations below, tell whether it is a homogeneous mixture or heterogeneous
VARVARA [1.3K]

Answer:

my family will visit our grandparents

4 0
3 years ago
Read 2 more answers
If a pork roast must absorb kJ to fully cook, and if only 10% of the heat produced by the barbecue is actually absorbed by the r
kolezko [41]

Answer:

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

Explanation:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g),\Delta H_{rxn}=-2044 kJ/mol (assuming)

Energy absorbed by pork,E = 1.6\times 10^3 kJ (assuming)

Total energy produced by barbecue = Q

Percentage of energy absorbed by pork = 10%

10\%=\frac{E}{Q}\times 100

Q=\frac{E}{10}\times 100=\frac{1.6\times 10^3 kJ}{10}\times 100=1.6\times 10^4 kJ

Since, it is a energy produced in order to indicate the direction of heat produced we will use negative sign.

Q = -1.6\times 10^4 kJ

Moles of propane burnt to produce Q energy =n

n\times \Delta H_{rxn}=Q

n=\frac{Q}{\Delta H_{rxn}}=\frac{-1.6\times 10^4 kJ}{-2044 kJ/mol}=7.83 mol

According to reaction , 1 mol of propane gives 3 moles of carbon dioxide. then 7.83 moles of will give:

\frac{1}{3}\times 7.83 mol=23.49 mol carbon dioxide gas.

Mass of 23.49 moles of carbon dioxide gas:

23.49 mol × 44 g/mol =1,033.56 g

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

8 0
3 years ago
What role do catalysts play in chemical reactions?
Ludmilka [50]
<em>Role of a catalysts in chemical reactions:</em>
<span><em>Catalyst is a substance, usually used in small amounts relative to the reactants, that modifies and increases the rate of a reaction without being consumed in the process.</em></span>

5 0
3 years ago
Consider the formation of nitrogen dioxide and oxygen: NO(g)+O3(g)⇌NO2(g)+O2(g) The reaction is first order in O3 and second ord
Leno4ka [110]

Answer:

The rate law is rate = k[NO][O₃]

Option E) is the right answer.

Explanation:

Hi there!

For this generic reaction:

A + B → products

the rate law will be:

rate = k[A]ⁿ[B]ᵃ

this reaction is n-order in A and a-order in B. The overall reaction is the sum of the orders of each reactant, in this case:

Overall order of the reaction = n + a

In our problem, we know that the reaction is first order in O₃ and second order overall. Then:

Overall order of the reaction = Order in NO + Order in O₃

2 = n + 1

2 - 1 = n

n = 1

Then, the reaction is first order in NO and first order in O₃.

The rate law will be:

rate = k[NO][O₃]

The right answer is the option E).

3 0
3 years ago
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