The following two questions refer to the circuit below. Consider a non-ideal op amp where the output can saturate. The open loop
gain A = 2 x 10^{4}10 4 , where v_{o}v o =−Av_{s}v s . The positive supply voltage for the op-amp is +V_S = 15+V S =15V. The negative supply voltage for the op-amp is -V_S = -10−V S =−10V. What is the most positive value v_{s}v s can take before the amplifier saturates? Express your answer in mV and omit units from your answer.
1 answer:
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Answer:
The answer is "26.55 V"
Explanation:
Given values:
For Answer (a) please find the attachment.
Answer (b):
