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Oliga [24]
3 years ago
12

Estimate the daily carbon utilization to remove chlorobenzene from 1.0 MGD of ground water saturated with chlorobenzene. Assume

a chlorobenzene concentration of 5 mg/L is acceptable for discharge to a POTW.
Contaminant = chlorobenzene [C_6H_5CI]
Final concentration of chlorobcnzene (C_f) = 5 mg/L
Saturation concentration = 500 mg/L
Density = 1.107 at 20°
Initial concentration = 500 mg/L
Freundlich isotherm:q or C_s = 91*Cf^0.99
Engineering
1 answer:
Setler [38]3 years ago
5 0

Answer:

4.6398 kg/day

Explanation:

Please find attached file for complete answer solution.

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Listed below are snippets from a prgram to perform input validation for
leva [86]

Answer:

#include <iostream>

#include <string>

#include "user.h"

#include "password.h"

using namespace Authenticate;

using namespace std;

int main()

{

inputUserName();

inputPassword();

cout << "Your username is " << getUserName() <<

" and your password is: " <<

getPassword() << endl;

return 0;

}

user.h:

#ifndef USER_H

#define USER_H

#include <string>

using namespace std;

namespace Authenticate

{

namespace

{

bool isvalid();

}

void inputUserName();

string getUserName();

}

#endif

user.cpp:

#include <iostream>

#include "user.h"

namespace Authenticate

{

string username="";

namespace

{

bool isvalid()

{

if(username.length() == 8)

return true;

else

return false;

}

}

void inputUserName(){

do

{

cout << "Enter your username (8 letters only)" << endl;

cin >> username;

}

while(!isvalid());

}

string getUserName()

{

return username;

}

}

password.h:

#ifndef PASSWORD_h

#define PASSWORD_h

#include <string>

using namespace std;

namespace Authenticate

{

namespace

{

bool isValid();

}

void inputPassword();

string getPassword();

}

#endif

password.cpp:

#include <iostream>

#include <string>

using namespace std;

namespace Authenticate

{

string password="";

namespace

{

bool isValid()

{

if(password.length() >= 8)

{

for(int i=0; i<password.length(); i++)

if(password[i] >= '0' && password[i] <= '9')

return true;

return false;

}

else

return false;

}

}

void inputPassword(){

do

{

cout << "Enter your password (at least 8 characters " <<

"and at leat one non-letter)" << endl;

cin >> password;

}

while(!isValid());

}

string getPassword()

{

return password;

}

}

3 0
3 years ago
A horizontal curve is being designed through mountainous terrain for a four-lane road with lanes that are 10 ft wide. The centra
ioda

Answer:

our answer is attached below

Explanation:

5 0
3 years ago
Before installing head gaskets look for “____” labels on the head gaskets
Strike441 [17]

Before installing head gaskets, you should look for "this side up" or "front" labels on the head gaskets.

<h3>What is a head gasket?</h3>

A head gasket can be defined as a gasket which is fitted between the engine block and the cylinder head in an internal combustion engine, so as to seal oil passages and absorb the pressures of the combustion that occurs inside the engine.

As a general rule, you should look for "this side up" or "front" labels on the head gaskets before installing head gaskets in an internal combustion engine of a vehicle.

Read more on head gaskets here: brainly.com/question/1264437

#SPJ1

7 0
2 years ago
Write what you already know about college majors. What are they? Can you think of any examples? When do you have to pick one? Ca
Mandarinka [93]
College majors are specific fields of study that help people prepare for career paths and learn content related to that subject. Some college majors would criminal justices, forensic science, gender studies, engineering, chemistry, and more. You should generally begin to research in your junior year of high school and select one by the beginning or your senior year for college applications. Once you get to college you can change your major.
5 0
3 years ago
Read 2 more answers
Air is a....<br> O Solid<br> O Liquid<br> O Gas<br> O Plasma
Galina-37 [17]

Answer:

Air is a gas

Explanation:

i think. beavuse it cant be a liqued or a solid. i dont think a plasma. i would answer gas

6 0
3 years ago
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