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Oliga [24]
3 years ago
12

Estimate the daily carbon utilization to remove chlorobenzene from 1.0 MGD of ground water saturated with chlorobenzene. Assume

a chlorobenzene concentration of 5 mg/L is acceptable for discharge to a POTW.
Contaminant = chlorobenzene [C_6H_5CI]
Final concentration of chlorobcnzene (C_f) = 5 mg/L
Saturation concentration = 500 mg/L
Density = 1.107 at 20°
Initial concentration = 500 mg/L
Freundlich isotherm:q or C_s = 91*Cf^0.99
Engineering
1 answer:
Setler [38]3 years ago
5 0

Answer:

4.6398 kg/day

Explanation:

Please find attached file for complete answer solution.

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PLS HELP! which statement is the best example of how society affects the useof technology? A. Farmers in hilly areas grow crops
Zielflug [23.3K]

Answer:

A

Explanation:

because  Farmers in hilly areas grow crops on terraces built on the hillsides.

7 0
2 years ago
At a certain location, wind is blowing steadily at 10 m/s. Determine the mechanical energy of air per unit mass and the power ge
ale4655 [162]

Answer:

<em>a) 50 J/kg</em>

<em>b) 721 67 KW</em>

<em></em>

Explanation:

The velocity of the wind v = 10 m/s

diameter of the blades d = 70 m

efficiency of the turbine η = 30%

density of air ρ = 1.25 kg/m^3

The area of the blade A = \pi d^2/4

A = \frac{3.142 * 70^2}{4} = 3848.95 m^2

The mechanical energy air per unit mass is gives as

e = v^2/2 = \frac{10^2}{2} = <em>50 J/kg</em>

<em></em>

Theoretical Power of the turbine P = ρAve

where

ρ is the density of air

A is the area of the blade

v is the velocity of the wind

e is the energy per unit mass

substituting values, we have

P = 1.25 x 3848.95 x 10 x 50 = 2405593.75 W

Actual power = ηP

where η is the efficiency of the turbine

P is the theoretical power of the turbine

Actual power = 0.3 x 2405593.75 = 721678.1 W

==> <em>721 67 KW</em>

7 0
3 years ago
(HVAC) PLEASE HELP neeed helpp
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Explanation
3 0
3 years ago
How long should the shafts remain in the furnace to achieve a desired centerline temperature of 800K? 2) Determine the temperatu
Phantasy [73]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

6 0
3 years ago
For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of t
Strike441 [17]

Answer:

the elongation of the metal alloy is 21.998 mm

Explanation:

Given the data in the question;

K = σT/ (εT)ⁿ

given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,

strain-hardening exponent n = 0.22

we substitute

K = 345 / 0.02^{0.22

K = 815.8165 Mpa

next, we determine the true strain

(εT) = (σT/ K)^1/n

given that σT = 412 MPa

we substitute

(εT) = (412 / 815.8165 )^(1/0.22)

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Now, we calculate the instantaneous length

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given that l_0 = 480 mm

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Now we find the elongation;

Elongation = l_i - l_0

we substitute

Elongation = 501.998 mm - 480 mm

Elongation = 21.998 mm

Therefore, the elongation of the metal alloy is 21.998 mm

6 0
3 years ago
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