A zener diode exhibits a constant voltage of 5.6 V for currents greater than five times the knee current. IZK is specified to be
1 answer:
Answer:
The maximum power dissipation of the zener diode 112mV.
Explanation:
The minimum zener current should be:
5 * Iza= 5 * 1= 5 mA.
Since the load current can be at maximum 15 mA, we should select R so that, IL= 15 mA.
A zener current of 5 mA is available, Thus the current should be 20 mA, which leads to,
R = = 470 Ω.
Maximum power dissipated in the diode occours when, IL=0 is
Pmax = 20 * * 5.6 = 112mV.
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Answer:
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Explanation:
Given
Required
Which paint does he have more?
For better understanding, it's better to convert both measurements to decimal.
For the green paint:
For the blue paint:
By comparison:
<em>This means that Jordan has more green paints</em>
Answer:
<em> - 14.943 W/m^2K ( negative sign indicates cooling ) </em>
Explanation:
Given data:
Area of FPC = 4 m^2
temp of water = 60°C
flow rate = 0.06 l/s
ambient temperature = 8°C
exit temperature = 49°C
<u>Calculate the overall heat loss coefficient </u>
Note : heat lost by water = heat loss through convection
m*Cp*dT = h*A * ( T - To )
∴ dT / T - To = h*A / m*Cp ( integrate the relation )
In ( ) = h* 4 / ( 0.06 * 10^-3 * 1000 * 4180 )
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hence h = - 0.2376 / 0.0159
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