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cricket20 [7]
3 years ago
5

What is the density of an block of salt having a mass of 8.0 g and a volume of 25 cm3?

Chemistry
2 answers:
iren [92.7K]3 years ago
8 0
Density is mass divided by volume
So...
D = 8/25 = 0.32 g/cm^3
Semmy [17]3 years ago
7 0
Do the formula <span>D = m/v </span>

d = ( 8.0 grams ) / ( 25 c ) 

d = 0.32 grams / c

<span>d = ( 0.32 g / c ) ( 1.0 x 10^6 c / c ) ( 1 kg / 1000 kg ) </span>

d = 320 kg / c

The answer is choice C. <span>✅</span>
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Bohr suggested, that there are definitive shells of particular energy and angular momentum in which an electron can revolve. It was not in Rutherford's model
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Salt is an ionic compount. it​
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Explanation:

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Can DNA evidence exclusively conclude ancestry?
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How many mols are present in the a sample of silver nitrate which has<br> 5.3x10^24 molecules.
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Answer:  5.3 x 10^24 formula units of silver nitrate is equivalent to 8.8 moles of silver nitrate. Silver nitrate is an ionic compound, therefore, its representative particle is called a "formula unit" instead of molecule. For every mole of a substance, we know that there are 6.022 x 10^23 representative units of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation:

We can convert from number of representative particles to moles using the formula:

\boxed {no. \ of \ moles \ = \ ( given \ no. \ of \ particles) \ (\frac{1 \ mole}{\ 6.022 \ x 10^{23} particles})}

For this problem, we can calculate the number of moles by plugging in the given values to the equation above,

no. \ of \ moles \ = (5.3 \ x \ 10^{24} \ formula \ units \ AgNO_{3}) \ (\frac{1 \ mole \ AgNO_{3}}{6.022 \ x 10^{23} \ formula \ units AgNO_{3}}) \\\\\boxed {no. \ of moles \ AgNO_{3} \ = \ 8.8 \ moles}

Learn More

  1. Learn more about representative particles brainly.com/question/8969313
  2. Learn more about Avogadro's number brainly.com/question/229300
  3. Learn more about mole conversions brainly.com/question/1370888

Keywords: moles conversion, Avogadro's number

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