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cricket20 [7]
3 years ago
5

What is the density of an block of salt having a mass of 8.0 g and a volume of 25 cm3?

Chemistry
2 answers:
iren [92.7K]3 years ago
8 0
Density is mass divided by volume
So...
D = 8/25 = 0.32 g/cm^3
Semmy [17]3 years ago
7 0
Do the formula <span>D = m/v </span>

d = ( 8.0 grams ) / ( 25 c ) 

d = 0.32 grams / c

<span>d = ( 0.32 g / c ) ( 1.0 x 10^6 c / c ) ( 1 kg / 1000 kg ) </span>

d = 320 kg / c

The answer is choice C. <span>✅</span>
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The base that will NOT combine with 2-deoxyribose to form a nucleic acid is _____.
beks73 [17]

Answer:

Uracil

Explanation:

The base that will NOT combine with 2-deoxyribose to form a nucleic acid is Uracil.

2-deoxyribose is a pentose sugar found in the DNA (Deoxyribonucleic acid). It is devoid of oxygen in its 2' position. The bases found in DNA are Adenine, Guanine, Cytosine and Thymine. Adenine, Guanine, and Cytosine are also found in RNA (Ribonucleic acid). Thymine is not present in RNA, it is only found in DNA. The base found in RNA is Uracil which in turn is not present in DNA. The five carbon sugar present in RNA is ribose which combines with Uracil.

3 0
3 years ago
A plant release it’s seed , but soon there after, the area seeds are in experiences a yearlong drought. How would the seeds most
SOVA2 [1]

Answer:

Plants will absorb water through their roots and release water as vapor into the air through these stomata. To survive in drought conditions, plants need to decrease transpiration to limit their water loss. Some plants that live in dry conditions have evolved to have smaller leaves and therefore fewer stomata.

Explanation:

Plants will absorb water through their roots and release water as vapor into the air through these stomata. To survive in drought conditions, plants need to decrease transpiration to limit their water loss. Some plants that live in dry conditions have evolved to have smaller leaves and therefore fewer stomata.

6 0
3 years ago
If kerosene has a specific gravity of 0.820, what force will be exerted on the circular bottom of a cylindrical kerosene tank th
Svet_ta [14]

Answer:

F = 774146.534\,N

Explanation:

The pressure at the bottom of the tank is:

P_{bottom} = (0.820)\cdot (1000\,\frac{kg}{m^{3}})\cdot (9.807\,\frac{m}{s^{2}})\cdot (30\,ft)\cdot (\frac{0.305\,m}{1\,ft} )

P_{bottom} = 73581.921\,Pa

The force exerted on the circular bottom is:

F=(73581.921\,Pa)\cdot (\frac{\pi}{4} )\cdot [(12\,ft)\cdot (\frac{0.305\,m}{1\,ft} )]^{2}

F = 774146.534\,N

4 0
3 years ago
True of False: Only conclusions that support the hypothesis should be reported in scientific research.
RSB [31]
False, If something doesn't support your hypothesis maybe it was wrong in the first place and you should make it known in your research if you come up with a different conclusion.
5 0
3 years ago
Read 2 more answers
If you have 3 moles of CH4 , how many moles of CO2 are produced?
k0ka [10]

Answer:

Since you are producing 3.6 mol CO2, you can calculate the starting moles of CH4 with the simple mole-to-mole ratio: 1 mol CH4 / 1 mol CO2 as a conversion factor. Taking 3.6 mol CO2 x 1 mol CH4 / 1 mol CO2 = 3.6 mol CH4 (after canceling out the moles of CO2 on the top and bottom of the calculation)

Explanation:

7 0
3 years ago
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