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ehidna [41]
2 years ago
13

What is the answer to this I am very confused

Chemistry
1 answer:
notka56 [123]2 years ago
6 0

Answer:C

Explanation:

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What do you mean by chemical reaction ?​
kherson [118]

A chemical reaction is a reaction that changes the molecular structure and is normally irreversible.

6 0
3 years ago
13. Would you expect oxygen to form a cation or anion? How many electrons would it gain or lose? Why?
netineya [11]

Answer: C)Anion, it would gain 2 electrons to satisfy the octet rule.

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies and thus the electronic configuration of oxygen with 8 electrons is

O:8:1s^22s^22p^4

The cation is formed by loss of electrons and anions are formed by gain of electrons.  

In order to complete its octet and get stable, it gains 2 electrons and thus would form an anion.

O^{2-}:10:1s^22s^22p^6

7 0
3 years ago
A 44.8 g rhodium sample contains how many rhodium atoms
Tresset [83]

Answer:

2.63*10^23

Explanation:

1 mol rhodium = 102.91

44.8g/1 mol * 1 mol/ 102.91mol * 6.022*10^23/1 mol =

2.63*10^23

6 0
3 years ago
A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
3 years ago
Iron and aluminum are examples of _____________.<br><br> <br><br>​
LenKa [72]

Answer:

Iron and aluminum are examples of metals, along with copper, iron, (etc.)

6 0
3 years ago
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