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notka56 [123]
3 years ago
7

how many moles of calcuim oxide are needed to react with an excess of water to form 370g of calcuim hydroxide

Chemistry
1 answer:
WINSTONCH [101]3 years ago
4 0

Answer:-

5

Explanation:-

Chemical formula for calcium oxide = CaO

Chemical formula of water = H2O

Chemical Formula of Calcium Hydroxide = Ca(OH)2

Mass of Ca(OH)2 = 370g

Molar mass of Ca(OH)2 = 40 x 1 + ( 16 x 1 + 1 x 1 ) x 2

= 74 g mol-1

Number of moles of Ca(OH)2 = 370 g / 74 g mol-1

= 5 moles

The balanced chemical equation for this process is

CaO + H2O --> Ca(OH)2

From the equation we see

For 1 mol of Ca(OH)2 to form, 1 mol of CaO is needed to react.

For 5 mol of Ca(OH)2 to form, 5 x 1 / 1 = 5 mol of CaO is needed to react.

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if you mixed 72.9g hydrochloric acid(aq) with 150g silver acetate(aq), what would be the limiting reagent?​
horsena [70]

Answer:

                      Silver Acetate would be the Limiting Reagent.

Explanation:

                    The balance chemical equation for the given double displacement reaction is as;

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Step 1: <u>Calculate Moles of Starting Materials:</u>

Moles of HCl:

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Moles of AgC₂H₃O₂:

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                      Moles  =  0.898 moles

Step 2: <u>Find out Limiting reagent as:</u>

According to balance chemical equation.

              1 mole of HCl reacts with  =  1 mole of AgC₂H₃O₂

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         1.99 moles of HCl will react with  =  X moles of AgC₂H₃O₂

Solving for X,

                     X =  1.99 mol × 1 mol / 1 mol

                     X =  1.99 mol of AgC₂H₃O₂

Hence, to completely consume 1.99 moles of Hydrochloric acid we will require 1.99 moles of Silver Acetate, But, we are provided with only 0.898 moles of Silver Acetate. This means Silver Acetate will consume first in the reaction therefore, it is the LIMITING REAGENT.

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