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erma4kov [3.2K]
3 years ago
15

Which occurs at a larger a wavenumber​

Chemistry
1 answer:
pav-90 [236]3 years ago
8 0

Answer:

The C-O stretch of phenol

Explanation:

Electron delocalization causes the of the phenol to have partial double bond character, whereas the  of the cyclohexanol is a pure single bond. Again, we know as the bond order or bond strength increases the absorption occurs at larger wave number. So, the  stretch of the phenol occurs at larger wave number.

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Answer: I think the answer is 2.5 M.

Explanation:  Formula: M = n/v

M= 10 mol / 4L

M= 2.5 M

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Khalad is measuring the amplitude of a wave. What can be known about this wave?
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B.It is a transverse wave
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If the conjugate base of a molecule has a pkb of 1.4, what would you expect the molecule to be?
maw [93]

If the conjugate base of a molecule has a pKb of 1.4, the molecule should be a Weak Acid.

Notice this question gives us the pKb of the molecule, not the pKa. Because of this, the pH scale basically gets reversed, so lower numbers in pKb correlate with stronger bases, and higher numbers in pKb correlate with stronger acids - the exact opposite of the pH scale.

It's important to make sure you completely understand the terms of conjugate base, conjugate acid, pKb, pKa, and how they all relate. It's easy to mix up the meanings of these definitions.

Here are the two other pieces of information you need to know to correctly answer this question:

  • Strong acids have a weak conjugate base.
  • Strong bases have a weak conjugate acid.

So if the problem says you have a strong conjugate base, then the molecule must be a weak acid. To illustrate this, think of ammonium, NH4+. Ammonium is a weak acid, but the conjugate base of ammonium is ammonia, NH3, which is a reasonably good base.

Learn more about conjugate base here : brainly.com/question/22514615

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3 0
2 years ago
23. The reaction
Sindrei [870]

Answer:

b mi disputa se eu não asetar

6 0
3 years ago
Determine the volume of 3.30 mol of a gas at 25°C and 0.995 atm.
Alexxx [7]

Answer:

V = 81.14 L

Explanation:

Given data:

Volume of gas = ?

Number of moles = 3.30 mol

Temperature of gas = 25°C

Pressure of gas = 0.995 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will convert the temperature.

25+273 = 298 K

now we will put the values in formula:

V = 3.30 mol 0.0821 atm.L/ mol.K   298 K / 0.995 atm

V = 80.74 L. atm / 0.995 atm

V = 81.14 L

4 0
3 years ago
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