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aleksley [76]
3 years ago
10

When comparing the two chair conformations for a monosubstituted cyclohexane ring, which type of substituent shows the greatest

preference for occupying an equatorial position rather than an axial position?
A. Polar substituents
B. Large substituents
C. Substituents with lone pairs
D. Small substituents

Chemistry
1 answer:
Klio2033 [76]3 years ago
6 0

Large substituents will chose equatorial conformation over axial conformation more readily.

<h3><u>Explanation</u>:</h3>

The axial conformation of the monosubstituted cyclohexane molecule is the Conformation where the substituted group is located along the axis of the molecule, perpendicular to the plane of the molecule. The equatorial conformation on the other hand is the substituted group being aligned along the plane of the molecule.

Now, in the axial position, the large groups will face steric hindrance with the axial hydrogens of the other carbon atoms which will lead the molecule more unstable. So larger is the group, more is the steric hindrance. So larger group will prefer the equatorial conformation more readily than the axial conformation.

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Answer:

<u>= 48.077 kcal </u>

Explanation:

The balanced equation is :

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Since the stoichiometric coefficient of Na2O = 1 hence its heat is  

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This means when 1 mole of the Na2O is burned , then 120 kcal of energy is released .

Molar mass of  Na2O = 2(mass of Na) + 1(mass of O)

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Molar mass = mass of the substance in grams present in 1 mole of it.

In 1 mole of Na2O , 61.97 gram of it is present.

Hence

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1 gram of Na2O =

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So,

24.8 gram of Na2O will produce,

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You can also proceed through mole concept:

Calculate number of moles in 24.8 gram Na2O

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So these many moles will produces:

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