Answer:
Answer for the given statements: (1) T , (2) F , (3) T , (4) F , (5) F
Explanation:
At the given interval, concentration of HI = 
Concentration of 
= 
Concentration of 
= 
Reaction quotient,
, for this reaction = ![\frac{[H_{2}][I_{2}]}{[HI]^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH_%7B2%7D%5D%5BI_%7B2%7D%5D%7D%7B%5BHI%5D%5E%7B2%7D%7D)
species inside third bracket represents concentrations at the given interval.
So, 
So, the reaction is not at equilibrium.
As 
therefore reaction must run in reverse direction to reduce and make it equal to 
. That means HI(g) must be produced and must be consumed.
Answer:
true
because with the both states we increase the surface of reaction
Moles of P = 56,4g/30,974g/mole = 1,82 moles P
moles of O = 43,6/15,999 = 2,73 moles of O
converting to the simplest ratio:
For P : 1,82/1,82 = 1
For O : 2,73/1,82 = 1,5
1 P and 2 oxygens.
PO2 -> the empirical formula
hope this help
<span>Sucrose is more soluble in water. The reason can be attributed to hydrogen bonding between water molecules and sucrose molecules. </span>
