A metallic bond can exist between atoms that have low ionization energies and
1 answer:
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For this reaction to proceed, the following bond breaking should occur:
*one C-H bond
* one Cl-Cl bond
After, the following bond formations should occur:
*one C-Cl bond
*one H-Cl bond
Now, add the bond energies for the respective bond energies which can be found in the attached picture. For bond formations, energy is negative. For bond breaking, energy is positive.
ΔHrxn = (1)(413) + (1)(242) + 1(-328) + 1(-431) = <em>-104 kJ</em>
*one C-H bond
* one Cl-Cl bond
After, the following bond formations should occur:
*one C-Cl bond
*one H-Cl bond
Now, add the bond energies for the respective bond energies which can be found in the attached picture. For bond formations, energy is negative. For bond breaking, energy is positive.
ΔHrxn = (1)(413) + (1)(242) + 1(-328) + 1(-431) = <em>-104 kJ</em>
Answer:
B) 1.65
Explanation:
See the image uploaded for the percent error formula
Work:
Theoretical Value - Accepted Value/Accepted Value * 100
= (24.7-24.3)/24.3 * 100
= 0.4/24.3 * 100
= 0.0164609053 * 100
= 1.64609053
Can be rounded to 1.65%
