All categories

2 years ago

Elabore el balance de la ecuación por oxido reducción enumerando cada paso

Chemistry

1 answer:

Rasek [7]2 years ago

8 0

Answer:

${ \rm{5CaC _{2}O _{4(aq)}+ 2KMnO _{4(aq)} + 8H _{2} SO _{4(aq)} → 5CaSO _{4(s)}+ 2Mn SO _{4(aq)}+ K _{2} SO _{4(s)} + 10CO _{2(g)} + 8H _{2} O _{l} }}$

Explanation:

This is a redox reaction formed by combining two half equations.

Check the image above, sorry if my handwriting is poor :(

You might be interested in

How many atoms of hydrogen are in 100 g of hydrogen peroxide (h2o2)?

Maurinko [17]

Hello friends..

find the MW of HP
calculate the # of mols per 100g of HP
take the # of mols times 6.023 x 10^23 times 2 (2 H per molecule)

Hope it helps you..

7 0

3 years ago

Which feature of four different marine fossils makes the fossil organism most similar to the present-day organism with four limb

zvonat [6]

I found the rest of the exercise on the internet and these are the options.
"-Undifferentiated vertebrae throughout the body.
-One neck vertebra allowing up and down movement.
-Many neck vertebrae that allow for greater mobility.
<span>-Two neck vertebrae allowing up and down and sideways movement."

The correct answer would be the third. - "</span>Many neck vertebrae that allow for greater mobility." The <span>present-day organism with four limbs has a neck with several vertebrae that allow movements of rotation (mostly because of only two vertebrae at the top of the neck), and side way movements, as well as back and forth movements.</span>

6 0

3 years ago

What does a Mitochondrion do

Slav-nsk [51]

Answer:

Explanation:

Power house of the cell.

It carries the DNA strand from the ribosome

3 0

3 years ago

Read 2 more answers

Calculate Ecell at 80 ºC for a voltaic cell based on the following redox reaction: H2(g, 1.25 atm) + 2AgCl(s) → 2Ag(s) + 2H+(aq,

iris [78.8K]

Answer:

Ecell = +0.25V

Explanation:

the half-cell reactions for a voltanic cell

cathode(reduction): 2H⁺(aq) + 2e⁻ ------- H₂(g)

anode(oxidation): 2AgCl(s) ------- 2Ag⁺(aq) + 2Cl⁻ + 2e⁻

we have the standard cell potential E⁺cell = 0.18V at 80C respectively

Q = [H⁺]/[Cl⁻]

sub for [H+] = 0.10M and [Cl-] = 1.5M

Q= 0.1M/1.5M

Q = 0.067

Ecell = E⁺cell - $\frac{0.059}{n}$ logQ

= 0.18 - $\frac{0.056}{1}$ log 0.067

0.18- 0.059(-1.174)

Ecell = +0.25V

6 0

3 years ago

A 25.0-mL sample containing Cu2+ gave an instrument signal of 25.2 units (corrected for a blank). When exactly 0.500 mL of 0.027

irga5000 [103]

Answer:

The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.

Explanation:

The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:

$C = \frac{n}{V} \\0.0275 = \frac{n}{0.0005} \\$

n = 1.375x10⁻⁵ mol

The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):

1.375x10⁻⁵ mol _________ 19.9 units

x _________ 25.2 units

x = 1.741x10⁻⁵mol

Finally, we can calculate the Cu²⁺ concentration :

C = 1.741x10⁻⁵mol / 0.025 L

C = 6.964x10⁻⁴ M

7 0

3 years ago