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Alex777 [14]
3 years ago
14

In a compressional wave the denser the medium is at the compressions the smaller is amplitude?

Physics
1 answer:
svlad2 [7]3 years ago
5 0
Wellll, let me think about that ...

I don't think I'd agree that you can characterize the amplitude of
a wave according to the density at only one point in it.  After all ...
a tiny wave in steel would be much denser at a compression than
a huge wave in air would be.

The amplitude of any wave is described as the difference between
a peak and the resting value.  Or even better ... half of the difference
between a maximum and a minimum.

So if you're looking at a longitudinal wave, like sound, I'd say if you
want to describe its amplitude, then you have to look at the density
at two points ... either the difference between the compression and
the resting densities, or the difference between the greatest compression
and the greatest rarefaction. 

That's my opinion.  I could be wrong.
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Answer:

Explanation:

When the positively charged half shell is brought in contact with the electroscope, its needle deflects due to charge present on the shell.

When the negatively charged half shell is brought in contact with the positively charged shell , the positive and negative charge present on each shell neutralises each other  .So both the shells lose their charges .The positive half shell also loses all its charges

When we separate the half shells , there will be no deflection  in the electroscope because both the shell have already lost their charges and they have become neutral bodies . So they will not be able to produce any deflection in the electroscope.

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3 years ago
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A student is preparing to bake a cake at home and places several ingredients on the countertop to use. First he preheats the ove
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Answer:

baking the cake batter

Explanation:

Baking the cake batter will indicate that chemical change has occurred here. What is a chemical change?

  • A chemical change is one in which a new kind of matter is formed.
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7 0
3 years ago
How much work is done if a force of 20 N moves an object a distance of 6 m?​
Nesterboy [21]

Explanation:

W=F×s

w=20N×6m=120J

W=120J

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3 years ago
How could you test the hypothesis that elephants interpreted the ground signal as being farther away than the air signal?
bekas [8.4K]

Answer:

One way to test the hypothesis is to create two waves, one in the air and one on the ground at the same time. One of them for the elephant to get closer and another for the elephants to move away. Observe the reaction of the animal and with this we know which sound came first.

Explanation:

This hypothesis is based on the fact that the speed of sound in air is v = 343 m / s with a small variation with temperature.

The speed of sound in solid soil is an average of the speed of its constituent media, giving values ​​between

 wood      3900 m / s

 concrete 4000 m / s

 fabrics     1540 m / s

 earth       5000 m / s wave S

 ground    7000 m / s P wave

 

we can see that the speed on solid earth is an order of magnitude greater than in air.

One way to test the hypothesis is to create two waves, one in the air and one on the ground at the same time. One of them for the elephant to get closer and another for the elephants to move away. Observe the reaction of the animal and with this we know which sound came first.

From the initial information, the wave going through the ground should arrive first.

3 0
4 years ago
A long straight wire carries a conventional current of 0.7 A. What is the approximate magnitude of the magnetic field at a locat
vfiekz [6]

Answer:

2.64 x 10⁻⁶T

Explanation:

The magnitude of the magnetic field produced by a long straight wire carrying current is given by Biot-Savart law as follows: "The magnetic field strength is directly proportional to the current on the wire and inversely proportional to the distance from the wire". This can be written mathematically as;

B = (μ₀ I) / (2π r)                ----------------(i)

B is magnetic field

I is current through the wire

r is the distance from the wire

μ₀  is the magnetic constant = 4π x 10⁻⁷Hm⁻¹

From the question;

I = 0.7A

r = 0.053m

Substitute these values into equation (i) as follows;

B =  (4π x 10⁻⁷ x 0.7) / (2π x 0.053)

B = 2.64 x 10⁻⁶T

Therefore the approximate magnitude of the magnetic field at that location is 2.64 x 10⁻⁶T

5 0
4 years ago
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