The maximum number of cubes that can be stacked on the inclined plane without sliding is determined as 8.
<h3>
Net force on the box</h3>
The net force on the box can be used to determine the maximum number of cubes that can be stacked without sliding.
The stack cubes must be at equilibrium.
∑Fx = 0
nW - μFₙ = 0
where;
- n is number of the cubes
- Fₙ is the normal force of the cubes
- W is the weight of the cubes acting parallel to the plane
n(mg)sinθ - μmgcosθ = 0
n(mg)sinθ = μmgcosθ
nsinθ = μcosθ
- let the coefficient of friction = 1
nsinθ = cosθ
n = cosθ/sinθ
n = 1/tanθ
n = (1)/(1/8)
n = 8
Thus, the maximum number of cubes that can be stacked on the inclined plane without sliding is determined as 8.
Learn more about cubes here: brainly.com/question/1972490
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Answer: Water fills the bucket until its force/weight is greater than the block’s. The lever tilts over, causing the bucket to water the plant.
Answer:
the velocity is zero, the acceleration is directed downward, and the force of gravity acting on the ball is directed downward
Explanation:
Is this exercise in kinematics
v = v₀ - g t
where g is the acceleration of the ball, which is created by the attraction of the ball to the Earth.
At the highest point
velocity must be zero.
The acceleration depends on the Earth therefore it is constant at this point and with a downward direction.
The force of the earth on the ball is towards the center of the Earth, that is, down
all other alternatives are wrong
Answer
given,
time = 10 s
ship's speed = 5 Km/h
F = m a
a is the acceleration and m is mass.
In the first case
F₁=m x a₁
where a₁ = difference in velocity / time
F₁ is constant acceleration is also a constant.
Δv₁ = 5 x 0.278
Δv₁ = 1.39 m/s
a₁ = 0.139 m/s²
F₂ =m x a₂
F₃ = F₂ + F₁
Δv₃ = 19 x 0.278
Δv₃ = 5.282 m/s
a₃=Δv₂ / t
a₃ = 0.5282 m²/s
m a₃=m a₁ + m a₂
a₃ = a₂ + a₁
0.5282 = a₂ + 0.139
a₂=0.3892 m²/s
F₂ = m x 0.3892...........(1)
F₁ = m x 0.139...............(2)
F₂/F₁
ratio = 
ratio = 2.8
Answer:
law of action and riactiond
