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2 years ago

Our ancestors are our guides?

Physics

1 answer:

aleksandr82 [10.1K]2 years ago

4 0

Answer:

yes

Explanation:

we can clearly say that our ancestor are our guide.

Because of they give us different knowledge about evolution of life and etc.

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Two point charges are arranged in a line with point P, which is on the right. The

MAVERICK [17]

Answer:

chicken

Explanation:

you like chicken and want to eat it

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2 years ago

57.9 g of gold has a volume of 3 cm³ what is the density of gold in g/ centimeters cubed

Grace [21]

D=m÷v

so density would be 57.9 ÷ 3 = 19.3 g/cm³

7 0

3 years ago

Read 2 more answers

to 10 Hz. Superimposed on this signal is 60-Hz noise with an amplitude of 0.1 V. It is desired to attenuate the 60-Hz signal to

givi [52]

Answer:

$G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1$

If we square both sides we got:

$G^2 (1+\frac{f}{f_c})^{2n}= 1$

We divide both sides by $G^2$ and we got:

$(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}$

Now we can apply log on both sides and we got:

$2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})$

And solving for n we got:

$n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}$

And replacing we got:

$n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}$

$n = \frac{4.60517}{3.8918}=1.18$

And since n needs to be an integer the correct answer would be n=2 for the filter order.

Explanation:

For this case we can use the formula for the Butterworth filter gain given by:

[tec] G = \frac{1}{\sqrt{1 +(\frac{f}{f_c})^{2n}}}[/tex]

Where:

G represent the transfer function and we want that G =0.1 since the desired signal is less than 10% of it's value

$f_c = 10 Hz$ represent the corner frequency

$f= 60 Hz$ represent the original frequency

n represent the filter order and that's the variable that we need to find

$G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1$

If we square both sides we got:

$G^2 (1+\frac{f}{f_c})^{2n}= 1$

We divide both sides by $G^2$ and we got:

$(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}$

Now we can apply log on both sides and we got:

$2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})$

And solving for n we got:

$n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}$

And replacing we got:

$n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}$

$n = \frac{4.60517}{3.8918}=1.18$

And since n needs to be an integer the correct answer would be n=2 for the filter order.

7 0

3 years ago

Explain the intermittent reinforcement schedules in your own words

fgiga [73]

In behaviorism, Intermittent Reinforcement is a conditioning schedule in which a reward or punishment (reinforcement) is not administered every time the desired response is performed. ... On an intermittent reinforcement schedule the mouse would only receive food every few times (it is typically random and unpredictable).

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3 years ago

Communicate is 25 a multiple of 2 or 5 ? how do you know?

PIT_PIT [208]

It's a multiple of 5 because you can't multiply anything by 2 and get 25

6 0

3 years ago

Our ancestors are our guides?​

Our ancestors are our guides?