Split the operation in two parts. Part A) constant acceleration 58.8m/s^2, Part B) free fall.
Part A)
Height reached, y = a*[t^2] / 2 = 58.8 m/s^2 * [7.00 s]^2 / 2 = 1440.6 m
Now you need the final speed to use it as initial speed of the next part.
Vf = Vo + at = 0 + 58.8m/s^2 * 7.00 s = 411.6 m/s
Part B) Free fall
Maximum height, y max ==> Vf = 0
Vf = Vo - gt ==> t = [Vo - Vf]/g = 411.6 m/s / 9.8 m/s^2 = 42 s
ymax = yo + Vo*t - g[t^2] / 2
ymax = 1440.6 m + 411.6m/s * 42 s - 9.8m/s^2 * [42s]^2 /2
ymax = 1440.6 m + 17287.2m - 8643.6m = 10084.2 m
Answer: ymax = 10084.2m
The potential difference between points a and b is zero.
<h3>Total emf of the series circuit</h3>
The total emf in the circuit is the sum of all the emf in the circuit.
emf(total) = 1.5 + 1.5 = 3.0 V
<h3>Potential difference</h3>
The potential difference between two points, a and b is calculated as follows;
V(ab) = Va - Vb
V(ab) = 1.5 - 1.5
V(ab) = 0
Thus, the potential difference between points a and b is zero.
Learn more about potential difference here: brainly.com/question/3406867
Answer:
B
Explanation:
The impulse experienced by an object is the force•time.
The ratio of the maximum photoelectron kinetic energy to the work function will be 3:1.
<h3 /><h3>What is the photoelectric effect?</h3>
When a medium receives electromagnetic radiation, electrostatically charged particles are emitted from or inside it.
The emission of ions from a steel plate when light falls on it is a common definition of the effect. The substance could be a solid, liquid, or gas; and the released particles could be protons or electrons.
A particular metal emits photoelectrons when exposed to light with energy three times its work function:
The ratio of the maximum photoelectron kinetic energy to the work function will be;
Hence, the ratio of the maximum photoelectron kinetic energy to the work function will be 3:1.
To learn more about the photoelectric effect refer to the link;
brainly.com/question/9260704
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Answer:
The compass will indicate a turn to the left.
Explanation:
The magnetic compass has a needle pointing towards north. It is used for navigation and it shows direction with respect to the geographical cardinal direction.
As we move to the right of the northerly heading in northern Hemisphere, the direction of needle will move towards left but with a faster rate as now the direction of north is no his left.
This shows the compass if following its direction properly.
