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umka2103 [35]
3 years ago
11

The molecular formulaof oxide of silicon​

Chemistry
2 answers:
natulia [17]3 years ago
8 0

Answer:

true

Explanation:

torisob [31]3 years ago
6 0

Answer:

The Molecular formula of oxide of silicon is SiO2

Explanation:

SiO2 is composed of oxide and silicon I hope this is very helpful, pardon me if this is incorrect

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Sorry it’s a bit blurry, you should be able to make it out

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4 years ago
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Given below is a list of chemical reactions. 1. Burning octane fuel 2. Forming rust in an iron pipe 3. Baking a cake 4. Cement h
Masja [62]
1, 3, 4, and 2 since rusting takes a long time and an example of rusting taking a long time is the Statue of Liberty.
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4 years ago
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The solubility product of calcium fluoride (CaF2(s); fluorite) is 310-11 at 25C. Could a fluoride concentration of 1.0 mg L-1
Finger [1]

The given question is incomplete. The complete question is as follows.

The solubility product of calcium fluoride () is  at 25 degrees C. Will a fluoride concentration of 1.0 mg/L be soluble in a water containing 200 mg/L of calcium?

Explanation:

Reaction equation for the given chemical reaction is as follows.

       CaF_{2} \rightleftharpoons Ca^{2+} + 2F^{-}

Therefore, expression for K_{sp} will be as follows.

        K_{sp} = [Ca^{2+}][F^{-}]^{2}

                     =

Also, moles of  per liter = \frac{\text{mass of F^{-} per L}}{\text{molar mass of F}}[/tex]

                = \frac{1.0 \times 10^{-3}}{19.0}

               = 5.263 \times 10^{-5} mol

Hence,    [F^{-}] = \frac{\text{moles of F^{-}}{volume}

                       = \frac{5.263 \times 10^{-5}}{1}

                      =  M

Now, moles of  per L = \frac{\text{mass of Ca^{2+} per L}}{\text{molar mass of Ca}}[/tex]

            = \frac{200 \times 10^{-3}}{40.1}

           =  M

Also,   [Ca^{2+}] = \frac{moles of Ca^{2+}}{volume}

                      = \frac{4.988 \times 10^{-3}}{1}

                     =  M

Hence, ionic product =

                 = (4.988 \times 10^{-3}) \times (5.263 \times 10^{-5})^{2}

                = 1.38 \times 10^{-11}

As, the ionic product is less than the K_{sp}, this means that the fluoride will be soluble in water containing the calcium.

4 0
3 years ago
Calculate the change in entropy if Br2(l) is converted into gaseous Br atoms.
mars1129 [50]

Answer:

197.8 J/(mol•K).

Explanation:

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<em>Br₂(l) ⟶ 2 Br(g)</em>

∴ ∆S° = [2 x S° Br(g)] - [S° Br₂(l)]

∴ ∆S° = [(2)(175.0 J/(mol•K)] - [152.2 J/(mol•K)] = 197.8 J/(mol•K).

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4 years ago
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The answer is MgBr2 (chemical formula of magnesium)
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