1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksenya-84 [330]
3 years ago
12

A 110.0-g sample of metal at 82.00°C is added to 110.0 g of H2O(l) at 27.00°C in an insulated container. The temperature rises t

o 30.56°C. Neglecting the heat capacity of the container, what is the specific heat of the metal? The specific heat of H2O(l) is 4.18 J/(g ∙ °C). Group of answer choices 4.18 J/(g ∙ °C) 60.4 J/(g ∙ °C) 0.289 J/(g ∙ °C) 0.289 J/(g ∙ °C) 14.4 J/(g ∙ °C)
Chemistry
2 answers:
erastovalidia [21]3 years ago
7 0

Answer:

The specific heat of the metal is 0.289 J/g°C

Explanation:

Step 1: Data given

Mass of metal = 110.0 grams

Temperature of the metal = 82.00 °C

MAss of water = 110.0 grams

Temperature of the water = 27.00 °C

The final temperature = 30.56 °C

The specific heat of H2O is 4.18 J/(g°C).

Step 2: Calculate the specific heat of the metal

Heat lost = heat gained

Qlost = - Qgained

Qmetal = - Qwater

Q =m*c*ΔT

m(metal)*c(metal)*ΔT(metal) = -m(water) * c(water) *ΔT(water)

⇒with m(metal) = the mass of the metal = 110.0 grams

⇒with c(metal) = the specific heat of the metal = TO BE DETERMINED

⇒with ΔT(metal) = the change of temperature of the metal = T2 - T1 = 30.56 - 82.00 °C= -51.44 °C

⇒with m(water) = the mass of water = 110.0 grams

⇒with c(water) = the specific heat of water = 4.18 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 30.56 °C - 27.00 °C = 3.56 °C

110.0 * c(metal) * -51.44 = -110.0 * 4.18 * 3.56

c(metal) = 0.289 J/g°C

The specific heat of the metal is 0.289 J/g°C

lina2011 [118]3 years ago
7 0

Answer:

Cp_{metal}=0.289\frac{J}{g^oC}

Explanation:

Hello,

In this case, as the water is cold (lower initial temperature) and the metal is hot (higher initial temperature), the heat lost by the metal is gained by the water to attain an equilibrium temperature of 30.56 °C, this in an equation turns out:

-\Delta H_{metal}=\Delta H_{water}

In such a way, in terms of masses, heat capacities and temperatures we have:

-m_{metal}Cp_{metal}(T_{eq}-T_{metal})=m_{water}Cp_{water}(T_{eq}-T_{water})

Hence, solving for the heat capacity of the metal:

Cp_{metal}=\frac{m_{water}Cp_{water}(T_{eq}-T_{water})}{-m_{metal}Cp_{metal}(T_{eq}-T_{metal})}

Thus, with the given data we obtain:

Cp_{metal}=\frac{110.0g*4.18\frac{J}{g^oC} (30.56^oC-27.00^oC)}{-110.0g(30.56^oC-82.00^oC)}\\\\Cp_{metal}=0.289\frac{J}{g^oC}

Best regards.

You might be interested in
Many scientists have been involved in the development of the theory of the structure of
Genrish500 [490]

Answer:

bohr descirbed the atomic structure and found that electrons travel in separate orbits around the nucleus. jj thomson created the plum pudding model.

7 0
2 years ago
Maggie has 4 binders with 30 stamps in each binder. She has 3 binders with 36 baseball cards in each binder. If she gives away 4
Sliva [168]

Answer:

The number of stamps and cards Maggie has left if she gives 45 stamps to a friend is 183

Explanation:

If Maggie gives 45 stamps to a friend, you must calculate the number of stamps and cards she has left.

You know Maggie has 4 folders with 30 stamps in each folder. So the number of stamps she owns is calculated as:

4 folders*30 stamps in each folder= 120 stamps

If Maggie gives 45 stamps to a friend, then the number of stamps she has left will be calculated as the difference (the subtraction) between the stamps she owned and the ones she gives away:

120 stamps - 45 stamps= 75 stamps

On the other hand, she has 3 binders with 36 baseball cards in each binder. So the number of cards she owns is calculated as:

3 binders * 36 baseball cards in each binders= 108 baseball cards

The number of stamps and cards you have left is calculated as:

75 stamps + 108 baseball cards= 183

<em><u>The number of stamps and cards Maggie has left if she gives 45 stamps to a friend is 183</u></em>

4 0
2 years ago
Finish the following word equation.<br><br> calcium + nitric acid →
Dafna1 [17]
HNO3 + Ca —-> H2O + N20 + Ca(NO3)2
4 0
3 years ago
if you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of
OverLord2011 [107]

Answer:

The mole fraction of codeine is 5.4%

Explanation:

Mole fraction = Mole of solute / Total moles (Mole solute + Mole solvent)

Solute (Codeine)

Molar mass 299.36 g/m

Mass / Molar mass = Mole →  46.85 g /299.36 g/m = 0.156 moles

Solvent (Ethanol)

Molar mass 46.07 g/m

125.5 g / 46.07 g/m = 2.724 moles

Mole fraction (Codeine) 0.156 / (0.156 + 2.724) → 0.054

3 0
3 years ago
A scientist asked a question that was based on an observation. What shou
nika2105 [10]
The scientist should form a hypothesis and design an experiment.

This way they can properly follow the scientific process.
3 0
3 years ago
Other questions:
  • Which of the following provides evidence that supports the continental drift theory? PLEASE HELP 10 POINTS
    14·2 answers
  • Write a nuclear equation for the decay of Polonium 211
    9·1 answer
  • Fill in the blanks: The original organism is called the _____________, and new organisms are called the _____________. Thx so mu
    13·1 answer
  • Hellpppppp pls it’s due in less than 10 min
    6·2 answers
  • Which of the following is least likely to increase the rate of diffusion?A small concentration gradientB higher concentration of
    14·1 answer
  • Main group elemants are arranged in _______ groups
    9·1 answer
  • The chemical equation shows the production of magnesium chloride.
    8·1 answer
  • A study is conducted to examine the effect of NaCl concentration on enzyme activity with the following results. Activity was tes
    11·1 answer
  • If an object is travelling 25.0 meters/second, how far will it travel in 45 minutes?
    13·1 answer
  • Radiation takes place with________ between a heat source and an object.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!