Answer:
11.1mL
Explanation:
The reaction expression is given as:
C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
Given parameters:
density of ethanol = 0.789g/mL
mass of CO₂ = 25g
Unknown:
Volume of ethanol = ?
Solution:
First find the number of moles of the CO₂ from the given mass;
Number of moles =
Molar mass of CO₂ = 12 + 2(16) = 44g/mol
Number of moles = = 0.57mol
Then;
Find the number of moles of ethanol used;
3 moles of CO₂ is produced from 1 mole of ethanol;
0.57mole of CO₂ will be produced from = 0.19mole of ethanol
Now;
Find the mass of the ethanol from the given mole;
Mass of ethanol = number of moles x molar mass
Molar mass of ethanol = 2(12) + 5(1) + 16 + 1 = 46g/mol
Mass of ethanol = 0.19 x 46 = 8.74g
Then;
Density is the mass per unit volume of a substance;
Density =
Volume =
Volume = = 11.1mL
Answer:concentration
Explanation:
In the first, the particles are much more concentrated, or close together, than in the second, where the particles are much more sparse.
Answer:
Mg(s) + 2NaF (aq) —> MgF₂ (aq) + 2Na(s)
Explanation:
Magnesium => Mg
Sodium fluoride => NaF
Magnesium fluoride => MgF₂
Sodium metal => Na
The equation can be written as:
Mg + NaF —> MgF₂ + Na
Thus, the above equation can be balance as illustrated below:
Mg + NaF —> MgF₂ + Na
There are 2 atoms of F on the right side and 1 atom on the left side. It can be balance by writing 2 before NaF as shown below:
Mg + 2NaF —> MgF₂ + Na
There are 2 atoms of Na on the left side and 1 atom on the right side. It can be balance by writing 2 before Na as shown below:
Mg + 2NaF —> MgF₂ + 2Na
Mg(s) + 2NaF (aq) —> MgF₂ (aq) + 2Na(s)
Now, the equation is balanced.
Answer: 3.73 grams
Explanation:
where Q= quantity of electricity in coloumbs
I = current in amperes = 96.0 A
t= time in seconds = 37.0 sec
The reaction at cathode is:
of electricity deposits 1 mole of
3552 C of electricity deposits = of Pb
Thus mass of lead deposited is 3.73 g
Answer:
50000mm u add subtract multiply divide
Explanation: