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Darya [45]
3 years ago
11

The density of aluminum is 2.7 g/cm3. A metal sample has a mass of 52.0 grams and a volume of 17.1 cubic centimeters. Could the

sample be aluminum? EXPLAIN your answer.
Chemistry
1 answer:
Alexus [3.1K]3 years ago
3 0

Answer:

The given metal sample is not aluminum because its density is 3.0 g/cm³ while density of aluminum is  2.7 g/cm³.

Explanation:

Given data:

Density of aluminum = 2.7 g/cm³

Mass of metal sample = 52.0 g

Volume of metal sample = 17.1 cm³

which sample is that = ?

Solution:

The given problem will be solve through density formula.

d = m/v

d = density

m = mass

v= volume

Now we will put the values in formula.

d = 52.0 g/ 17.1 cm³

d = 3.0 g/cm³

It is given in question the density of aluminum is 2.7 g/cm³. The given metal sample is not aluminum because its density is 3.0 g/cm³.

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3 years ago
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Lilit [14]
It is A. Barium

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Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802
Anvisha [2.4K]

Answer:

1 gramo de metano aporta 50.125 kilojoules.

1 gramo de metano aporta 48.246 kilojoules.

Explanation:

La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo (Q), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto (\bar {Q}), en kilojoules por mol, dividido por su masa molar (M), en gramos por mol:

Q = \frac{\bar Q}{M} (1)

A continuación, analizamos cada caso:

Metano

Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }

Q = 50.125\,\frac{kJ}{g}

1 gramo de metano aporta 50.125 kilojoules.

Octano

Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }

Q = 48.246\,\frac{kJ}{mol}

1 gramo de metano aporta 48.246 kilojoules.

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17.0 g of Cl_2 has a volume of 9.22 L at 17°C. What is its pressure?
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