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Darya [45]
2 years ago
11

The density of aluminum is 2.7 g/cm3. A metal sample has a mass of 52.0 grams and a volume of 17.1 cubic centimeters. Could the

sample be aluminum? EXPLAIN your answer.
Chemistry
1 answer:
Alexus [3.1K]2 years ago
3 0

Answer:

The given metal sample is not aluminum because its density is 3.0 g/cm³ while density of aluminum is  2.7 g/cm³.

Explanation:

Given data:

Density of aluminum = 2.7 g/cm³

Mass of metal sample = 52.0 g

Volume of metal sample = 17.1 cm³

which sample is that = ?

Solution:

The given problem will be solve through density formula.

d = m/v

d = density

m = mass

v= volume

Now we will put the values in formula.

d = 52.0 g/ 17.1 cm³

d = 3.0 g/cm³

It is given in question the density of aluminum is 2.7 g/cm³. The given metal sample is not aluminum because its density is 3.0 g/cm³.

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<u>Answer:</u> The net ionic equation for the given reaction is 2H^+(aq.)+SO_3^{2-}(aq.)\rightarrow H_2O(l)+SO_2(g)

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are the ions which do not get involved in a chemical equation. It is also defined as the ions that are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of hydrochloric acid and potassium sulfite is given as:

2HCl(aq.)+K_2SO_3(aq.)\rightarrow 2KCl(aq.)+SO_2(g)+H_2O(l)

Ionic form of the above equation follows:

2H^+(aq.)+2Cl^-(aq.)+2K^+(aq.)+SO_3^{2-}(aq.)\rightarrow 2K^+(aq.)+2Cl^-(aq.)+SO_2(g)+H_2O(l)

As, potassium and chloride ions are present on both the sides of the reaction, thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

2H^+(aq.)+SO_3^{2-}(aq.)\rightarrow SO_2(g)+H_2O(l)

Hence, the net ionic equation for the given reaction is written above.

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