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3 years ago

What belief do Deists hold about the universe?

2 answers:

8 0

"<span>b. God had created a mechanistic universe that could only be understood through the Bible" is the best option since Deists believe God treats the universe in a "hands off" way. </span>

SSSSS [86.1K]3 years ago

6 0

its b because god did create a mechanistic universe

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an underground explosion generates sound waves that travel through solid rock, then through a lake and then air. describe how th

DIA [1.3K]

Answer: sound can slow down, so when it travels through all of that it's muffled and kind of blocked. sound travels at 332 metres per second so it's hard to stop the sound

Explanation:

7 0

3 years ago

Decane (C10H22) is used in diesel. The combustion for decane follows the equation: 2 C10H22 + 31 O2 à 20 CO2 + 22 H2O. Calculate

creativ13 [48]

The mass of water produced is 792 grams by the combustion of 568 grams of decane.

Given:

Combustion of 568 grams of decane with 2979 grams of oxygen.

$2 C_{10}H_{22 }+ 31 O_2 \rightarrow 20 CO_2 + 22 H_2O$

To find:

The mass of water produced by combustion of 568 grams of decane.

Solution:

Mass of decane = 568 g

Moles of decane :

= $\frac{568 g}{142 g/mol}=4 mol$

Mass of oxygen gas = 2976 g

Moles of oxygen gas:

= $\frac{2976 g}{32 g/mol}=93 mol$

$2 C_{10}H_{22 }+ 31 O_2 \rightarrow 20 CO_2 + 22 H_2O$

According to reaction, 2 moles of decane reacts with 31 moles of oxygen, then 4 moles of decane will react with:

$=\frac{31}{2}\times 4mol=62\text{ mol of}O_2$

But according to the question, we have 93.0 moles of oxygen gas which is more than 62 moles of oxygen gas.

So, this means that oxygen gas is present in an excessive amount. Which simply means:

Oxygen gas is an excessive reagent.
Decane is a limiting reagent.
Decane being limiting reagent will be responsible for the amount of water produced after the reaction.

According to reaction, 22 moles of water is produced from 2 moles of decane, then 4 moles of decane will produce:

$=\frac{22}{2}\times 4mol=44\text{mol of }H_2O$

Mass of 44 moles of water ;

$=44mol\times 18g/mol=792g$

792 grams of water is produced by the combustion of 568 grams of decane.

Learn more about limiting reagent and excessive reagent here:

brainly.com/question/14225536?referrer=searchResults

brainly.com/question/7144022?referrer=searchResults

3 0

3 years ago

F O R 50 P O I N T S !!!

nika2105 [10]

Answer:

You would put the 4 quantum numbers corresponding to the electrons being described above

Explanation:

Quantum numbers refer to electrons, so I'll assume you mean the electron number that would correspond with the atomic number of the element. Quantum numbers are basically like an address for electrons, giving us information about the location of an electron from most general to most specific.

8 0

3 years ago

blast furnaces give off many unpleasant and unhealthy gases. If the total air pressure is .99 ATM the partial pressure of carbon

kolbaska11 [484]

Answer:

$P_{air}=1.02atm$

Explanation:

Hello!

In this case, since the Dalton's law help us to realize that the total pressure of a gas mixture is computed by adding the partial pressure of each composing gas, for the mixture formed by carbon dioxide, oxygen sulfide (should be hydrogen sulfide instead) and air, we can write:

$P=P_{CO_2}+P_{H_2S}+P_{air}$

Thus, given the total pressure and the partial pressures of both carbon dioxide and hydrogen sulfide, the partial pressure of the remaining air would be:

$P_{air}=P_{T}-P_{H_2S}-P_{CO_2}$

Therefore, we plug in to obtain:

$P_{air}=0.99atm-0.05atm-0.02atm\\\\P_{air}=1.02atm$

Best regards!

6 0

3 years ago

How much salt (NaCl) is carried by a river flowing at 30.0 m3/s and containing 50.0 mg/L of salt

denis23 [38]

Answer:

129,600kg/day

Explanation:

The river is flowing at 30.0

1 m³ is equivalent to 1000L

flowrate of river = 30*1000 =30,000L/s

Convert L/s to litre per day by multiplying by 24*60*60

flowrate of river = 30,000 * 24*60*60 L/day

= 2,592,000,000L/day

if the river contains 50mg of salt in 1L of solution

lets find how many mg of salt Y is contained in 2,592,000,000L/day

by cross multiplying we have

Y= $\frac{2592000000*50}{1}$

Y= 129,600,000,000 mg/day

convert this value to kg/day by dividing by 1 million

Y= 129,600,000,000/1000000

Y= 129,600kg/day

3 0

3 years ago