Answer:
The initial temperature of the metal is 84.149 °C.
Explanation:
The heat lost by the metal will be equivalent to the heat gain by the water.
- (msΔT)metal = (msΔT)water
-32.5 grams × 0.365 J/g°C × ΔT = 105.3 grams × 4.18 J/g °C × (17.3 -15.4)°C
-ΔT = 836.29/12.51 °C
-ΔT = 66.89 °C
-(T final - T initial) = 66.89 °C
T initial = 66.89 °C + T final
T initial = 66.89 °C + 17.3 °C
T initial = 84.149 °C.
Answer:
<h2>The answer is 3.0 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass of aluminum = 8.1 g
density = 2.7 g/mL
It's volume is

We have the final answer as
<h3>3.0 mL</h3>
Hope this helps you
Answer:
Its the bottom one :) ......