Carbon dioxide is a chemical compound composed of one carbon and two oxygen atoms. It is often referred to by its formula CO2. It is present in the Earth's atmosphere at a low concentration and acts as a greenhouse gas. In its solid state, it is called dry ice. It is a major component of the carbon cycle.
Answer:2H₂+ O₂→ 2H₂O the reactants are 2H₂ and O₂ ... if the theoretical yield is 95 g of water after the chemical reaction you may have only 45g of water
i think
Explanation:
4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.
<h3>What are Noble Gases ?</h3>
The noble gases are helium, argon, krypton, xenon, and radon, in order of their mass.
They are called noble gases because they are so majestic that they do not react with anything in general.
The work done can be calculated by the formula
Q=n Cp ΔT
Cp= ( 1+ f/2)R
R= 8.3144598 J. mol-1.
Cp = (1+3/2) * 8.314
Cp = 5*8.314/2
Q= 2 * 5 *8.314 *100/2
Q = 4157 J
Therefore 4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.
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Answer : The enthalpy change of reaction is -23.9 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given final reaction is,

The intermediate balanced chemical reaction will be,
(1)

(2)

First we will reverse the reaction 1 and multiply equation 2 by 3 then adding both the equation, we get :
(1)

(2)

The expression for final enthalpy is,



Therefore, the enthalpy change of reaction is -23.9 kJ
Base on the question and in my further research and investigation about the said problem that states to identify the type of bonding in solid potassium, I would say that the bondings are metallic bonding and metallic. I hope you are satisfied with my answer and feel free to ask for more