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Alisiya [41]
3 years ago
15

The current in a closed circuit measures 80 amps. The resistance through a clock connected in the circuit is 2 ohms. What is the

voltage of the circuit?
a
40 volts
b
110 volts
c
160 volts
d
60 volts
the subject is SCIENCE
Chemistry
1 answer:
nydimaria [60]3 years ago
5 0
C. 160 Volts

Explanation;
V: Voltage
I: Current (Amps)
R: Resistance (Ohms)
Meaning you would have to multiply (80 amps x 2 ohms) giving you 160 Volts.
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If you have a block of plastic and a block of copper that are the same mass and are placed in the sun for 10 minutes. What is th
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INFORMATION:

Is given that:

- if you have a block of plastic and a block of copper that are the same mass and are placed in the sun for 10 minutes.

And after the 10 minutes copper has a higher temperature.

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STEP BY STEP EXPLANATION:

To determine it, we need to know the concept of specific heat

If the block of copper has a higher temperature after 10 minutes, that means copper needs less heat to raise its temperature.

So, plastic has a higher specific heat than metal, so it takes more energy to heat plastic than copper. As a result, plastic would heat up more slowly.

ANSWER:

The explanation for the copper having a higher temperature after 10 minutes in the sun, is that plastic has a higher specific heat than metal, so it takes more energy to heat plastic than copper. As a result, plastic would heat up more slowly. Since the copper has a lower specific heat, it will be heat quickly.

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What must be true for a spontaneous reaction in an electrochemical cell? The overall cell potential must be positive. The overal
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The overall cell potential must be positive.

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What must be true for a spontaneous reaction in an electrochemical cell?

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Answer :  The mole fraction and partial pressure of CH_4,CO_2 and He gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.

Explanation : Given,

Moles of CH_4 = 1.79 mole

Moles of CO_2 = 1.20 mole

Moles of He = 3.71 mole

Now we have to calculate the mole fraction of CH_4,CO_2 and He gases.

\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CH_4=\frac{1.79}{1.79+1.20+3.71}=0.267

and,

\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CO_2=\frac{1.20}{1.79+1.20+3.71}=0.179

and,

\text{Mole fraction of }He=\frac{\text{Moles of }He}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

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Thus, the mole fraction of CH_4,CO_2 and He gases are, 0.267, 0.179 and 0.554 respectively.

Now we have to calculate the partial pressure of CH_4,CO_2 and He gases.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 5.78 atm

X_i = mole fraction of gas

p_{CH_4}=X_{CH_4}\times p_T

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p_{CO_2}=X_{CO_2}\times p_T

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and,

p_{He}=X_{He}\times p_T

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Thus, the partial pressure of CH_4,CO_2 and He gases are, 1.54, 1.03 and 3.20 atm respectively.

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