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4 years ago

5

Which substance has the highest density at room temperature?

1 answer:

12345 [234]4 years ago

6 0

I think phosphorus has the highest density at room temp.

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As heat is added to a substance undergoing a phase change, the temperature remains constant because the energy is being used to

viktelen [127]

Overcome intermolecular forces

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3 years ago

This will blow ur brains

Akimi4 [234]

Uhhhhh that’s crazy

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3 years ago

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A football player pushes against another player trying to block him from moving any farther down the field. Which term best desc

Ira Lisetskai [31]

Answer:

negative work is done.

Explanation:

Here a football player pushes against another player so the force is applied by the football player so that it will move ahead Now here the force of another player is opposite to his motion so the work done on player by another player is negative.

So work done is negative because it is done on the system.

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3 years ago

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The primary of a step-down transformer has 240 turns and is connected to a 120 V rms line. The secondary is to supply 26 A at 6

julia-pushkina [17]

Explanation:

Solution (1)

It is given that,

Number of turns in primary coil in step down transformer, $N_P=240$

Voltage in primary transformer, $V_p=120\ V$

Current in secondary coil, $I_s=26\ A$

Voltage in secondary coil, $V_s=6\ A$

(a) Let $I_P$ is the current in primary coil. It can be calculated using the formula as :

$\dfrac{V_P}{V_s}=\dfrac{I_s}{I_P}$

$\dfrac{120}{6}=\dfrac{26}{I_P}$

$I_p=1.3\ A$

(b) Let $N_s$ is the number of turns in secondary coil. It can be calculated using the formula as :

$\dfrac{V_P}{V_s}=\dfrac{N_P}{N_s}$

$\dfrac{120}{6}=\dfrac{240}{N_s}$

$N_s=12\ turns$

Solution (2)

Capacitance of the capacitor, $C=8\ \mu F=8\times 10^{-6}\ F$

Voltage, V = 33 V

Inductance, $L=11\ mH=11\times 10^{-3}\ H$

(a) Let E is the energy stored in the system. It is given by :

$E=\dfrac{1}{2}CV^2$

$E=\dfrac{1}{2}\times 8\times 10^{-6}\times (33)^2$

E = 0.00435 J

or

$E=4.35\times 10^{-3}\ J$

(b) Let f is the frequency of oscillation. It is given by :

$f=\dfrac{1}{2\pi \sqrt{LC} }$

$f=\dfrac{1}{2\pi \sqrt{11\times 10^{-3}\times 8\times 10^{-6}} }$

f = 536.51 Hz

(c) The maximum current in the circuit is,

$I=\sqrt{\dfrac{2E}{L}}$

$I=\sqrt{\dfrac{2\times 0.00435}{11\times 10^{-3}}}$

I = 0.88 A

Hence, this is the required solution.

5 0

3 years ago

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Một tải có điện trở R = 19ohm đấu vào nguồn điện một chiều có E = 100V,

klio [65]

Answer:

Hindi ko alma yam among twang yan

Explanation:

aorry

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3 years ago