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3 years ago

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A bird flies overhead from where you stand at an altitude of 270.0ĵ m and at a velocity horizontal to the ground of 14.0î m/is.

The bird has a mass of 2.3 kg. The radius vector to the bird makes an angle θ with respect to the ground. The radius vector to the bird lies in the xy-plane. What is the bird's angular momentum (in kg · m2/s) about the point where you are standing

1 answer:

Varvara68 [4.7K]3 years ago

8 0

Answer:

L = 8694 Kg.m²/s

Explanation:

r = 270 ĵ m

v = 14 î m/s

m = 2.3 kg

θ = 90º

L = ?

We can apply the equation

L = m*v*r*Sin θ

L = (2.3 kg)*(14 m/s)*(270 m)*Sin 90º = 8694 Kg.m²/s

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Stolb23 [73]

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