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Vinvika [58]
3 years ago
15

Instrument used to measure the length of a football field​

Physics
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

If you need to measure much longer lengths - for example the length of a football pitch - then you could use a trundle wheel. You use it by pushing the wheel along the ground. It clicks every time it measures one metre.

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A student makes a simple pendulum by attaching a mass to the free end of a 1.50-meter length of string suspended from the ceilin
Fofino [41]

Answer:

The mass has likely lost some of its mechanical energy to resistance on its path.

Explanation:

The mechanical energy of an object is the sum of its kinetic and potential energies (KE and PE.) Ideally, the mechanical energy of a simply pendulum should be "conserved." In other words, the sum of the kinetic and potential energy of the simply pendulum should stays the same as it travels along its path.

Indeed, as the pendulum travels, some of its PE will convert to KE and back. However, the sum of these two energies is supposed to stay the same.

  • When the pendulum moves from the highest point to the bottom of the path, some of its PE converts to KE. (The pendulum speeds up in this process.)
  • When the pendulum moves from the bottom of its path to the opposite side, its KE is converted back to PE. (The pendulum slows down as it moves towards the other side of the path.)

However, in practice, the mechanical energy of pendulums isn't always conserved. For example, various kinds of resistances (such as air resistance) act on the pendulum as it moves. That would slow down the pendulum. Some of the pendulum's energies would be converted to heat and is lost to the surroundings.

In effect, the mechanical energy of the pendulum would become smaller and smaller over time. When the pendulum travels back towards the girl, its potential energy would be smaller than the initial value when at the girl's chin.

5 0
3 years ago
An astronaut is rotated in a horizontal centrifuge at a radius of 5.0 m. (a) What is the astronaut’s speed if the centripetal ac
sergeinik [125]

Explanation:

Given that,

Radius of circular path, r = 5 m

Centripetal acceleration, a=7g\ m/s^2

(a) Let v is the astronaut’s speed. The formula for the centripetal acceleration is given by :

a=\dfrac{v^2}{r}

v=\sqrt{ar}

v=\sqrt{7\times 9.8\times 5}

v = 18.5 m/s

(b) Let T denotes the time period. It is given by :

T=\dfrac{2\pi r}{v}

T=\dfrac{2\pi \times 5}{18.5}

T = 1.69 s

Let N is the number of revolutions. So,

N=\dfrac{60}{1.69}=35.5\ rev/min

So, the number of revolutions per minute is 35.5

(c) T = 1.69 seconds

Hence, this is the required solution.

8 0
3 years ago
The pressure of a box pushes down on the floor is 50 Pa if the box weighs 400 N what is the area of the base of the box
Wewaii [24]

Answer:8m^2

Explanation:

Area=force÷pressure

Area=400÷50

A=8m^2

5 0
3 years ago
How much work does it take to lift 345 boxes to a height of 6.00 m of each box has a mass of 7.89 kg
Art [367]

Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

<h3>Work done</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where F is force applied or Weight and d is distance

Also Force = Weight = mass × acceleration due to gravity.

Since gravity is acting on the boxes as it been lift

W = Weight × height from ground level

W = mg × d

Where m is mass of the boxes, g is accelration due to gravity( g = 9.8m/s² ) and d is distance from ground level.

Given the data in the question;

  • Since each box has a mass of 7.89 kg
  • Mass of the 345 boxes = 345 × 7.89 kg = 2722.05kg
  • Distance or height d = 6.0m
  • Work done W = ?

To determine the work done, we substitute our values into the expression above.

W = mg × d

W = 2722.05kg × 9.8m/s² × 6.0m

W = 160056.5kgm²/s²

W = 160056.5J

W = 1.6 × 10⁵J

Therefore,  Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

Learn more about work done here: brainly.com/question/26115962

3 0
2 years ago
What force is required to accelerate a 1840 kg car from 4.77 m/s to 23.5 m/s,
neonofarm [45]
A :-) for this question , we should apply
a = v - u by t
Given - u = 4.77 m/s
v = 23.5 m/s
t = 5.18 m/s
Solution -
a = v - u by t
a = 23.5 - 4.77
a = 28.27 m/s^2

.:. The acceleration is 28.27 m/s^2
7 0
3 years ago
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