All categories

3 years ago

Find the value of 5 ∙ 23.

Mathematics

1 answer:

GREYUIT [131]3 years ago

4 0

5 * 23 is equal to 115. =)

You might be interested in

How to simplify -3(x+4)-(x-3)

aev [14]

Step-by-step explanation:

$-3(x+4)-(x-3) \\ - 3x - 12 - x - 3 \\ - 4x - 15 \\ - 4x = 15 \\ x = - \frac{15}{4}$

4 0

3 years ago

a 42 inch diameter tablecloth that hangs off the edge 8 inches. what is the area of the tablecloth use 3.14 for pi

joja [24]

Answer: 1384.74

Step-by-step explanation:

A=πr^2

radius=42/2=21

(3.14)(21)^2

3.14(441)

1384.74

3 0

3 years ago

770,070 in expanded form

Shalnov [3]

700,000 + 70,000 + 70

is your answer

hope this helps :D

4 0

3 years ago

Read 2 more answers

Solve the problem algebraically. Clearly define all variables, write an appropriate equation, and solve.

hichkok12 [17]

Answer:

Y=8 and X=21

Step-by-step explanation:

The key to solving word (story) problems is to learn how to translate words and phrases into concise, precise math expressions (variables and operations). Make a table and add to it as you do problems:

is means =

more than +

twice 2*x

sum +

of usually means multiply

...

Assign variables. Try to assign variables to the values the problem asks you to find.

In this problem, there are two variables. Let x = one number; y = other numbers

Translate:

"One number is 5 more than twice the other number" means

x = 5 + 2 * y

"sum of the two numbers is 29" means

x + y = 29

Now, the easy math.

Use the value for x from the first equation and substitute that into the second equation:

(5 + 2y) + y = 29

5 + 3y = 29 (collect terms)

3y = 24 (subtract 5 from both sides)

y = 8

Now, put that value of y into either equation to solve for x (Which equation is easier??)

x + 8 = 29

x = 21 (subtract 8 from both sides)

Checking (very important):

Is 21 really 5 more than 2(8)?

21 = 5+16 ?

21 = 21? yes

Is 21 + 8 = 29 ?

29 = 29? yes

p.s., learn the process, don't just get the right answer; there will be lots of problems that are solved the same way!

3 0

1 year ago

In the square below, the two semi-circles are congruent. Find the area of the shaded region. If necessary, round your answer to

Jobisdone [24]

Let's start with the area of the square
$area \: square = s \times s = 8 \times 8 = 64$
now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches

$area \: circle = \pi {r}^{2} = \pi \times {4}^{2} = 16\pi$
now we just subtract and our answer is

$64 - 16\pi = 64 - 16 \times (3.14) = 13.73$

3 0

3 years ago