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oksano4ka [1.4K]
3 years ago
13

Determine how many subatomic particles are in the following days

Chemistry
1 answer:
ololo11 [35]3 years ago
6 0

Answer:

Number of protons in Na²⁴ = 11

Number of neutrons in Na²⁴ = 13

Number of electrons in Na²⁴ = 11

Number of protons in I¹³¹ = 53

Number of neutrons in I¹³¹ = 78  

Number of electrons in I¹³¹  = 53

Explanation:

Sodium is present in group one.

Atomic number of sodium is 11.

Its atomic mass is 23 amu.

Electronic configuration:

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

Number of protons in Na²⁴ = 11

Number of neutrons in Na²⁴ = 13 (24-11= 13)

Number of electrons in Na²⁴ = 11

Iodine:

Iodine is halogen element.

Its atomic number is 53.

Its atomic mass is 127 amu.

Electronic configuration:

I₅₃= [Kr] 4d¹⁰ 5s² 5p⁵

Number of protons in I¹³¹ = 53

Number of neutrons in I¹³¹ = 78  (131-53= 78)

Number of electrons in I¹³¹  = 53

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An element like silicon is not usually used to make wires or pans because it?
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It is not good conductors of electricity or heat!
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Which one is denser? question 2 options: the earth (a solid object) the sun, which is about 300,000 times more massive than the
tankabanditka [31]
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3 years ago
An object has balanced forces acting on it. Which of the following describes the result these balanced forces have on the object
dexar [7]

Answer:

C.It remains at rest or moves at constant speed in the same direction.

Explanation:

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An object acted by balanced forces is said to be at equilibrium, thus the state of motion will be maintained.The object will not accelerate. A good example of an object acted by balanced forces is an object at rest or in constant motion such as a car that stopped at red-light signal or a car travelling at a constant speed.

4 0
3 years ago
What concentrations of acetic acid (pKa = 4.76) and acetate would be required to prepare a 0.15 M buffer solution at pH 5.0? Not
Leni [432]

Answer:

Acetic acid 0,055M and acetate 0,095M.

Explanation:

It is possible to prepare a 0,15M buffer of acetic acid/acetate at pH 5,0 using Henderson-Hasselblach formula, thus:

pH = pka + log₁₀ [A⁻]/[HA] <em>-Where A⁻ is acetate ion and HA is acetic acid-</em>

Replacing:

5,0 = 4,76 + log₁₀ [A⁻]/[HA]

<em>1,7378 =  [A⁻]/[HA] </em><em>(1)</em>

As concentration of buffer is 0,15M, it is possible to write:

<em>[A⁻] + [HA] = 0,15M </em><em>(2)</em>

Replacing (1) in (2):

1,7378[HA] + [HA] = 0,15M

2,7378[HA] = 0,15M

[HA] = 0,055M

Thus, [A⁻] = 0,095M

That means you need <em>acetic acid 0,055M</em> and <em>acetate 0,095M</em> to obtain the buffer you need.

i hope it helps!

7 0
3 years ago
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