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oksano4ka [1.4K]
4 years ago
13

Determine how many subatomic particles are in the following days

Chemistry
1 answer:
ololo11 [35]4 years ago
6 0

Answer:

Number of protons in Na²⁴ = 11

Number of neutrons in Na²⁴ = 13

Number of electrons in Na²⁴ = 11

Number of protons in I¹³¹ = 53

Number of neutrons in I¹³¹ = 78  

Number of electrons in I¹³¹  = 53

Explanation:

Sodium is present in group one.

Atomic number of sodium is 11.

Its atomic mass is 23 amu.

Electronic configuration:

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

Number of protons in Na²⁴ = 11

Number of neutrons in Na²⁴ = 13 (24-11= 13)

Number of electrons in Na²⁴ = 11

Iodine:

Iodine is halogen element.

Its atomic number is 53.

Its atomic mass is 127 amu.

Electronic configuration:

I₅₃= [Kr] 4d¹⁰ 5s² 5p⁵

Number of protons in I¹³¹ = 53

Number of neutrons in I¹³¹ = 78  (131-53= 78)

Number of electrons in I¹³¹  = 53

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Answer: 17 years

Explanation:

Expression for rate law for first order kinetics  for radioactive substance is given by:

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Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

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4 0
3 years ago
From this list, choose all of the ionic compounds. Check all that apply. View Available Hint(s) Check all that apply. POCl3 KOCH
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Answer: KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

Explanation:

It is known that ionic compounds are the compounds in which one atom transfer its valence electrons to another atom. Hence, during this transfer partial opposite charges tend to develop on the combing atoms due to which strong force of attraction exists between the atoms.

An ionic bond is always formed between a metal and a non-metal.

For example, KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

On the other hand, a compound formed due to sharing of electrons between the combining atoms is known as a covalent compound. Generally, a non-metal with same or different non-metal tends to form a covalent bond.

For example, POCl_{3}, SOCl_{2} etc are all covalent compounds.

Thus, we can conclude that KOCH_2CH_3, [tex]CH_3CH_2COONa, NaOH are all ionic compounds.

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Answer:

The reaction is zero order with respect to B

Explanation:

The reaction given in the question is -

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