Answer:
V2 = 0.75 L
Explanation:
assumin ideal gas:
∴ T1 = 300K
∴ V1 = 0.500 L
∴ T2 = 450 K
⇒ V2 = ?
assuming P, n constant:
⇒ PV1 = RT1n
⇒ V1/T1 = Rn/P = K..........(1)
⇒ V2/T2 = RN/P = K..........(2)
(1) = (2):
⇒ V1/T1 = V2/T2
⇒ V2 = (V1/T1)T2
⇒ V2 = (0.500 L/300 K)(450 K)
⇒ V2 = 0.75 L
Answer:
the answer is 2 by 3
Explanation:
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Answer:
The solubility product of lead(II) chloride is
.
Explanation:
Concentration of lead (II) ions = ![[Pb^{2+}]=0.0159 M](https://tex.z-dn.net/?f=%5BPb%5E%7B2%2B%7D%5D%3D0.0159%20M)
Concentration of chloride ion = ![[Cl^-]=0.0318 M](https://tex.z-dn.net/?f=%5BCl%5E-%5D%3D0.0318%20M)

The expression of a solubility product will be given as:
![K_{sp}=[Pb^{2+}][Cl^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E-%5D%5E2)

The solubility product of lead(II) chloride is
.