Question

Calculate the pH of solutions prepared by a. Dissolving 4.8 g of lithium hydroxide in water to give 250 mL of solution

Answer 1

pH of the solution is 13.90.

What is pH ?

The concentration of hydrogen (H+) ions in a solution, which is a measurement of acidity, is known as the pH of that solution. In pure water, hydrogen and hydroxyl (OH) ions are found in almost equal amounts.

A solution is acidic when there are too many hydrogen ions present, while a solution is basic when there are too few H+ ions or too many hydroxyl ions. The product of the concentrations of H+ and OH is the equilibrium constant for this reaction, Kw, which equals 10^14.

Given:

Mass of lithium = 4.8 g

Volume of the solution = 250 mL

Formula used :

[H3O+] = Kw/ [OH-]

Where,

[H3O+] : hydronium ion concentration

[OH-] : hydroxyl ion concentration

Kw : Equilibrium constant

Solution:

moles of LiOH = 4.8/23.95 = 0.20 moles

strength of LiOH = 4 x 0.20 = 0.80 M

[H3O+] = Kw/ [OH-] = 10^(-14) / 0.80 = 1.25 x 10 ^(-14)

pH = - log [H3O+]

pH = - log ( 1.25 x 10 ^ (-14)) = 13.90

Therefor, pH is 13.90

To learn more about pH :

brainly.com/question/491373

#SPJ4