Answer:
???
Explanation:
What specifically are you asking about
Answer:
Explanation:
a = (vf - vi)/ t
A a = (5 - 15) / 10 = - 1 m/s²
B a = (25 - 30) / 15 = - 1/3 m/s²
C a = (25 - 20) / 2 = 5/2 m/s²
D a = (-15 - (-10)) / 3 = -5/3 m/s
from most negative to most positive
D, A, B, C
Answer:
386 m
Explanation:
Let's call the horizontal distance between the point of launch and the point of landing of the first package
.
2 seconds after landing at
, the plane has travelled a horizontal distance of
.
At this new point, the second package is launched. Because it is launched under the same conditions as the first, its horizontal distance from its point of launch is also
.
To determine
, we determine the time of fall of the package. Being a vertical motion, the drop has an initial velocity,
, of 0 m/s with acceleration,
, and a distance,
, of 160 m. We use the equation of motion:



In this time, the package, with a horizontal velocity of 50 m/s, travels the horizontal distance,
, of

The distance apart between both packages is 
IF you're in Arlington TX, THEN the line of +32.7 declination on the celestial sphere is always directly over your head in the sky.
Elements protons and electrons are balanced, so the answer is 33.