Answer:
Distance, S = 130m
Explanation:
Given the following data;
Initial velocity = 2m/s
Final velocity = 28m/s
Acceleration = 3m/s²
To find the distance, we would use the third equation of motion.
V² = U² + 2aS
Substituting into the equation, we have;
28² = 2² + 2*3*S
784 = 4 + 6S
6S = 784 - 4
6S = 780
S = 780/6
False -> negative charge
d a
t=1.25s
The formula is
a= (V1-V0) /t
t = (V1-V0)/a
V1=50m/s
V0= 0 m/s
a= - 4m/s2
t= (0-50)/-4 = 1.25s