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olganol [36]
3 years ago
8

Which expressions are equivalent to the one below? Check all that apply. log2 16 + log2 16 A. log2(28) B. 8 C. log 256 D. log2 2

56
Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

log2^256

log2(2^8)

8

Step-by-step explanation:

Just did it on A P E X

And these were correct

eduard3 years ago
3 0

Answer:

B. 8.

D.  log2 256.

Step-by-step explanation:

Generally:

loga b + loga b

= loga b^2.

Therefore log2 16 + log2 16

= log2 16^2

= log2 256.

From the above:

256 = 2^x   where x is the log.

Now 2^8 = 256   so the original log2 16 + log2 16 = 8.

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PLEASE HELP 11 points
tatuchka [14]

Answer:

12.56

Step-by-step explanation:

6 0
3 years ago
Expand the following:3/4(-24x-16)​
Illusion [34]

Answer:

-18x-12

Step-by-step explanation:

3/4(-24x-16)=-18x-12

4 0
3 years ago
20 to 8 in simpliest form
Mashcka [7]

Answer:

in it's lowest form its 5/2

8 0
2 years ago
Find the area of the shaded region
ale4655 [162]

Answer:

379.56ft²

Step-by-step explanation:

Oh lordy why, okay we got this:

So we're going to start with the area of the square, this is easy because all of the sides are 25ft, so we just have to plug into our formula for squares (base x height):

25 x 25 = 625

Now we have to do the semicircle, remember that the formula for the area of a circle is pi x radius², we're using 3.14 for pi, so we have to find the radius (half the diameter):

25 ÷ 2 = 12.5

12.5² = 156.25

3.14 x 156.25 = 490.625‬

Normally we would stop here, but because this is only a semicircle, we have to divide by two:

490.625‬ ÷ 2 = 245.3125‬

So, now that we have our two areas, we have to subtract the semicircle from the square:

625 - 245.3125‬ = 379.6875‬

Now, I realize that his answer isn't in your cute little word bank, but that because I rounded pi, so the closest is 379.56

So, the area of the figure is 379.56ft²

if this is wrong let me know so I can fix it

hope this helps:)

5 0
3 years ago
Sin0=12/37 find tan0
alexira [117]

Answer:

\large{ \tt{❃ \: EXPLANATION}} :

  • We're provide - Sin θ = \frac{12}{37} which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = \tt{  \frac{p}{h}} ] . We're asked to find out tan θ ].

\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :

\large{ \tt{❊ \:  {h}^{2}  =  {p}^{2}  +  {b}^{2} }}

\large{ \tt{⇢ {p}^{2} +  {b}^{2}   =  {h}^{2} }}

\large{ \tt{⇢ \:  {b}^{2}  =  {h}^{2}  -  {p}^{2} }}

\large{ \tt{⇢ \:  {b}^{2} = {37}^{2} -  {12}^{2}   }}

\large{ \tt{⇢ \:  {b}^{2}  = 1369 - 144}}

\large{ \tt{ ⇢{b}^{2}  = 1225}}

\large{ \tt{⇢ \: b =  \sqrt{1225}}}

\large{ \tt{⇢ \: b = 35  \: \text {units}}}

  • Now , We know - Tan θ= \tt{ \frac{perpendicular}{base} }. Just plug the values :

\large{ \tt{➝ \: Tan  \: \theta =  \frac{p}{b}  = \boxed{ \tt{  \frac{12}{35} }}}}

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5 0
3 years ago
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