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2 years ago

PLZ ANSWER THE QUESTION FROM THE PICTURE ASAP 20 POINTS

Mathematics

1 answer:

almond37 [142]2 years ago

8 0

Answer:

Step-by-step explanation:

The recursive rule is given by;

a = r .an-1 where n is the number of terms.

Given the sequence: -64, -16, -4 , -1, ....

This sequence is a geometric sequence with common ratio (r) = 1/4

Here, first term a1 = -64

Since,

\frac{-16}{-64} = \frac{1}{4}

\frac{-4}{-16} = \frac{1}{4} and so on....

The recursive rule for this sequence is;

an = 1/4*an-1

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I need help proving this ASAP

Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

$\tan(x + \frac{3\pi}{2} ) = - \cot \: x$

One way is to use the basic double angle formula:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ \sin(x) \cos( \frac{3\pi}{2} ) + \cos(x) \sin( \frac{3\pi}{2}) }{\cos(x) \cos( \frac{3\pi}{2} ) - \sin(x) \sin( \frac{3\pi}{2}) }$

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ \sin(x) ( 0) + \cos(x) ( - 1) }{\cos(x) (0) - \sin(x) ( - 1) }$

We simplify further to get:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ 0 - \cos(x) }{0 + \sin(x) }$

We simplify again to get;

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{- \cos(x) }{ \sin(x) }$

This finally gives:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = - \cot(x)$

6 0

3 years ago

the difference of two number is 28 if the larger number is three time of the smaller find the number

Elza [17]

Set up an equation:

3x - x = 28

Simplify:

2x = 28

Divide both sides by 2

X = 14

3(14) = 42

The numbers are 42 and 14

5 0

2 years ago

Show work and Evaluate 3/4 + 2/5

frez [133]

Answer:

23/20

Step-by-step explanation:

Find the common denominator of the 2 fractions (It's 20):

3/4 + 2/5

Multiply both numerator and denominator by 5 for the first fraction and multiply by 4 for the second fraction:

15/20 + 8/20

Add the fractions together:

23/20

5 0

2 years ago

If 3 + root8 by 3-root8 + 3-root8 by 3+root8 = a+broot2 find a and b

s2008m [1.1K]

If $\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}$ , the value of a and b is given as a = 34 and b = 0

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables or numbers.

$\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }\\ \\\frac{9+6\sqrt{8}+8+9-6\sqrt{8}+8 }{(3-\sqrt{8} )(3+\sqrt{8} )} \\\\\frac{34}{9-8} =34+0\sqrt{2}$

If $\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}$ , the value of a and b is given as a = 34 and b = 0

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0

2 years ago

What is the area of the figure below please explain!

jeyben [28]

I don't know the area of a parallelogram off the top of my head but you can use the area of the rectangle and the area of the triangle and add those. The area of the triangle is 1/2*base*height and use the pythagorean theorem to find the base. 3² + b² = 5²; 9 + b² = 25; b² = 16; b = 4. The area of the triangle is 1/2*4*3 or 6 in. Since there are two of them, the total area of the triangles are 12 in. The area of the rectangle is length*width or (12 - 4) * 3 which is 8 * 3 or 24in. Add these areas together to get 36in total

4 0

3 years ago

PLZ ANSWER THE QUESTION FROM THE PICTURE ASAP 20 POINTS ​

PLZ ANSWER THE QUESTION FROM THE PICTURE ASAP 20 POINTS