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gladu [14]
3 years ago
6

What is the surface area and volume of this prism?

Mathematics
2 answers:
timurjin [86]3 years ago
7 0
Surface Area = 2×(15×10 + 15×8 + 10×8) = <span>700 foot<span>2</span></span>
NeX [460]3 years ago
7 0
Volume is 8*10*15 because height times width times length
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Marion left out reasons from her proof. Which reason best supports the statement?
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Corresponding angle postulate
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What is the area of a rectangular holding pond with length 8/15 mile and width 1/6 mile?
SSSSS [86.1K]

as you already know, the area of a rectangle is just length*width, so is just the product of those two.


\bf \cfrac{8}{15}\times \cfrac{1}{6}\implies \cfrac{8}{6}\times \cfrac{1}{15}\implies \cfrac{4}{3}\times \cfrac{1}{15}\implies \cfrac{4}{45}

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Which of the following is the graph of f(x) = 3 sin (2x)? (2 points)
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Step-by-step explanation:

4 0
3 years ago
What is the mean median and mode of 99, 69, 96, 69, 78. Round to the nearest tenth if necessary
KiRa [710]
A median is the middle number of a data set.
To find it put the numbers in order.
78, 69, 69, 96, 99
Then find the middle number
78, 69, *69,* 96, 99

The median is 69

A mode is the number that appears the most in a set of numbers.
78, *69, 69,* 96, 99

The mode is 69

To find the mean or average of a set of numbers, add all the numbers together then divide by the number of numbers there are.
99+69+96+69+78 = 411
411/5 = 82.2

The mean is 82.2

Hope this helped! If you have anymore questions or don't understand, please comment on my profile or DM me. :)
6 0
3 years ago
Can someone explain the process getting from:
spin [16.1K]
\rm 5=e^{3b}

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.

We'll take log of each side.
Log of what base tho?

Well, the base of our exponential is e,
so we'll take log base e of each side.

\rm log_e(5)=log_e(e^{3b})

We'll apply one of our log rules next:
\rm \log(x^y)=y\cdot\log(x)

This allows us to take the exponent out of the log,

\rm log_e(5)=(3b)log_e(e)

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
\rm log_{10}(10)=1
\rm log_5(5)=1
\rm log_e(e)=1

So our equation simplifies to this,

\rm log_e(5)=(3b)\cdot1

As a final step, divide both sides by 3,

\rm \frac13log_e(5)=b

k, hope that helps!


6 0
3 years ago
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