Answer:
the radius of the base is equal to ![x=2\sqrt[3]{\frac{105}{\pi } }](https://tex.z-dn.net/?f=x%3D2%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%20%7D%20%7D)
And the height is equal to:
![y=\frac{840}{\pi(2\sqrt[3]{\frac{105}{\pi}})^{2} }](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B840%7D%7B%5Cpi%282%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%7D%7D%29%5E%7B2%7D%20%7D)
Step-by-step explanation:
We write the volume function
where x is the radius of the base and y is the height of the cylinder

The surface of a cylinder is given by
on the interval from 0 to infinity
We now determine the critical values by differentiating and making the equation equal to 0

This equation have 2 complex solutions and one real solution
![x=2\sqrt[3]{\frac{105}{\pi } }](https://tex.z-dn.net/?f=x%3D2%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%20%7D%20%7D)
For x=0 and infinity the equation goes to infinity also so the radius of the base is equal to ![x=2\sqrt[3]{\frac{105}{\pi } }](https://tex.z-dn.net/?f=x%3D2%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%20%7D%20%7D)
And the height is equal to:
![y=\frac{840}{\pi (2\sqrt[3]{\frac{105}{\pi } })^{2} }](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B840%7D%7B%5Cpi%20%282%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%20%7D%20%7D%29%5E%7B2%7D%20%7D)
![y=\frac{840}{\pi(2\sqrt[3]{\frac{105}{\pi}})^{2} }](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B840%7D%7B%5Cpi%282%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%7D%7D%29%5E%7B2%7D%20%7D)
Answer:
11
Step-by-step explanation:
3+3+5
3+3
=6
6+5
=11
hope this was helpful! <3
Answer:
A basic formula, solving for x, guides us in the setting up of an equation: D/H x Q = x, or Desired dose (amount) = ordered Dose amount/amount on Hand x Quantity
Step-by-step explanation:
Medications are available in multiple concentrations, therefore orders written in "mL" rather than "mg" are not acceptable and require further clarification.
...
Example 2.
Step 1. Calculate the dose in mg: 18 kg × 100 mg/kg/day = 1800 mg/day
Step 2. Divide the dose by the frequency: 1800 mg/day ÷ 1 (daily) = 1800 mg/dose
Can you give me some hint please