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marshall27 [118]

4 years ago

10

Which part of Earth Is hotter ? Which part is colder ? Why ?

1 answer:

LekaFEV [45]4 years ago

5 0

Explanation:

Dasht-e Loot, Iran is the hottest,, and the coldest is the East Antarctic Plateau. The reason that part of Iran is the hottest is because it's near the Arabian deserts, and as you know the deserts can be pretty hot. The coldest part of the Earth is that cold because it doesn't get as much sunlight, the reason for that is because they don't get any direct sunlight.

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Is adequate health care are available to all

tankabanditka [31]

Explanation:

I think for anyone to answer this we need more info on what you want answered. The Sentence Itself doesn't Make Since To Me

6 0

2 years ago

Water changes from a liquid to a gas in the process of evaporation. Please select the best answer from the choices provided T F

const2013 [10]

The correct answer is T.

6 0

4 years ago

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Brilliant_brown [7]

Temperatures above 100 are gases

8 0

3 years ago

What frequency is received by the ambulance after reflecting from a wall near the person watching the oncoming ambulance (as in

Zepler [3.9K]

Answer:

900.48925 Hz

979.9785 Hz

Explanation:

$v_a$ = Relative velocity of ambulance = $109\ km/h=\dfrac{109}{3.6}$

$v_w$ = Velocity of wall = 0

v = Velocity of sound in air = 343 m/s

From doppler effect we have

$f=f'\dfrac{v+v_w}{v-v_a}\\\Rightarrow f=821\dfrac{343+0}{343-\dfrac{109}{3.6}}\\\Rightarrow f=900.48925\ Hz$

The frequency of sound is 900.48925 Hz

When the wall acts like a source

$f=f'\dfrac{v+v_a}{v-v_w}\\\Rightarrow f=900.48925\dfrac{343+\dfrac{109}{3.6}}{343-0}\\\Rightarrow f=979.9785\ Hz$

The frequency of sound is 979.9785 Hz

4 0

3 years ago

A force is applied to the rim of a disk that can rotate like a merry-go-round, so as to change its angular velocity. Its initial

yawa3891 [41]

Answer:

A = B = C > D

Explanation:

Work done to stop the disc is given as

$W = \Delta K$

$W = \frac{1}{2}I(\omega_f^2 - \omega_i^2)$

so we have

(a) –2 rad/s, 5 rad/s;

(b) 2 rad/s, 5 rad/s;

(c) –2 rad/s, –5 rad/s; and

(d) 2 rad/s, –5 rad/s.

So we have

$W_a = W_b = W_c = \frac{1}{2}I(5^2 - 2^2)$

$W_d = \frac{1}{2}I(2^2 - 5^2)$

so we have

A = B = C > D

5 0

3 years ago