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m = 80 kg
R = 6.4 x 10^6 m
Earth completes one rotation in 24 hours
Thus, T = 24 x 3600 s
Centripetral acceleration is given by
ac = w^2R
ac = (2 pie/T)^2R
ac = (2 pie/T)^2R = 4 pie^2/(24 x 3600)^2 x 6.4 x 10^6
ac = 0.034 m/s^2
Answer:
greater acceleration is experienced by the car with lower mass
Explanation:
Since both the toys are connected by same spring so the force due to spring on both the toys will be same and it is given as

now we know by Newton's II law

so here we have

here we have same force on both the blocks
so acceleration will be more if mass is less
so greater acceleration is experienced by the car with lower mass
Answer:
a) 4.31 m/s²
b) 215.5 m
Explanation:
a) According to Newton's first law of motion
The net force applied to particular mass produced acceleration, a, according to
F = ma
F = 140 N
m = 32.5 kg
a = ?
140 = 32.5 × a
a = 140/32.5 = 4.31 m/s²
b) Using the equations of motion, we can obtain the distance travelled by the object in t = 10 s
u = initial velocity of the probe = 0 m/s (since it was initially at rest)
a = 4.31 m/s²
t = 10 s
s = distance travelled = ?
s = ut + at²/2
s = 0 + (4.31×10²)/2 = 215.5 m
Since we are only looking at the vertical height, we can use the free fall equation to find the height:
h = 0.5*g*t^2, where h is height in m, g is acceleration due to gravity (9.81 m/s^2), and t is time in seconds
h = 0.5*(9.81 m/s^2)*(3.7 s)^2
h = 67.15 m
Therefore, the 7th floor window is 67.15 m above ground level.