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Natalka [10]
3 years ago
10

Which situation below most likely causes a theory to change?

Physics
1 answer:
Sergio039 [100]3 years ago
5 0

Answer:

A new technology is invented that allows for new experimentation.

Explanation:

This should be the best situation because new technology helps scientists make more accurate and precise experiments, usually giving changes to the old experiments, and the discovery of newer parameters that could not have been found in the old experiment.

So new technology, more accurate and precise experiments, more parameters and conditions have been found, giving scientists a deeper understanding of what is happening, therefore giving a theory a high probability to change.

You might be interested in
Zach runs a 100-meter race. 7 seconds after the race started Zach is 35 meters from the starting line and reaches his max speed;
Angelina_Jolie [31]

Answer:MaxSpeed=8 m/s. Additional distance during z seconds after top speed is 8*z meters. Now the distance at 7+z seconds after the race starts is D=( 35+8*z) meters. For x ≥ 7 the time of the race, then  D=(35+(x-7)*8) meters is the distance traveled during that time.

Explanation:

First we are interested in calculating the top speed, that is constant. We know at 35 meters he reaches the top speed and this happens 7 seconds after the race started. Also he is at 75 meters from the starting line 12 seconds after the beginning, then we can use the definition of speed, in this case is constant, to get its value:  Speed=change in distance / change in time

Then Speed= (75-35)meters/(12-7)seconds = 40m/5s=8m/s. That is the topspeed=8 m/s  

Now from the 35 meters he runs at constant speed, then if we are told he runs z seconds and we are asked the distance he runs in that time, we know the distance at constant speed is D=V*t,

then D= 8m/s * z seconds=8z meters.

But here since the run is a 100 meters-race we have an upper bound for z, here he has left (100-35)=65 meters to run at 8m/s, then he can maximum run additional 8,125 second or 15,125 seconds in total for the race.

That is D=8*z meters, with z < 8,125 seconds, this is the additional distance he can run after reaching his top speed.

Now the distance at 7+z seconds after the race starts is D=( 35+8*z) meters, the first 35 m he runs until reaching his top speed and the rest of the distance at this speed.

for x the total time of the run at a given point, we are asked the distance he has traveled at that time, then we are also told x ≥ 7, then  D=(35+(x-7)*8) meters, we subtract the 7 initial seconds because they are already counted in the initial 35 meters.

7 0
4 years ago
Calculate the minimum thickness (in nm) of an oil slick on water that appears blue when illuminated by white light perpendicular
mr_godi [17]

Answer:

The minimum thickness = 83.92 nm

Explanation:

The relation between the wavelength in a particular medium and refractive index \lambda_n = \frac{ \lambda }{n}

where ;

\lambda = wavelength of the light in vacuum

n = refractive index of medium with respect to vacuum

For one phase change :

2t = \frac{\lambda_n}{2}\\\\where \ \lambda_n = \frac{\lambda}{n}\\\\Then \ \\\\2t = \frac{\lambda}{2n}\\\\t = \frac{\lambda_n}{4n}

Replacing 1.43 for n and 480 nm for λ; we have:

t = \frac{480}{4(1.43)}

t = 83.92 nm

Thus; the minimum thickness = 83.92 nm

4 0
3 years ago
On the incomplete ray diagram for an object in front of a curved mirror, trace the path of Ray 1 as you would do to find the loc
Alisiya [41]

Answer:

<u></u>

  • <u>See attached the ray diagram with the path of Ray 1, which must pass through the focal point, F.</u>

Explanation:

The <em>curved mirror</em> shown is a converging lens.

<em>To find the location and size of the image</em> formed by a converging lens, you must draw two rays: one ray is from the upper tip of the object (the pen in your figure) that is in front of the mirror, parallel to the horizontal axis until the lens (<em>Ray 1</em> in your figure) which then bends through the focal point (F in your figure). That is the ray that you must complete in your figure.

The attached figure shows this ray in blue.

The other ray would be from the upper tip of the pen straight through the center of the lens (this is not included in the figure, by instructions of the question).

4 0
3 years ago
Use the second laws of thermodynamics to explain how an incandescent bulb might be less efficient than a compact fluorescent bul
Vsevolod [243]

An incandescent bulb produces light that comes from the heating of a filament. A compact fluorescent bulb produces light when a substance is hit by electromagnetic radiation. Compact fluorescent bulbs are more efficient than incandescent bulbs.

The first law of thermodynamics is a version of the law of conservation of energy, adapted for thermodynamic processes. Therefore, a system with lower heat emissions would be more efficient.

The second law of thermodynamics states that the total entropy of an isolated system (the thermal energy per unit temperature that is unavailable for doing useful work) can never decrease. In our context, it means that the system with the least amount of losses would be more efficient. As a conclusion the fluorescent bulb would be more efficient.

8 0
2 years ago
A forward-biased silicon diode is connected to a 6.0-V battery. Also in the circuit are three 220 Ω resistors connected in serie
o-na [289]

Answer:

Current in the circuit will be 0.024 A

Explanation:

We have given battery voltage v = 6 volt

Resistance R = 220 ohm

Diode potential v_d = 0.7 volt

So voltage across the resistance = 6 - 0.7 = 5.3 volt

Current is given by current=\frac{voltage}{reistance}=\frac{5.3}{220}=0.024A

So current in the circuit will be 0.024 A

3 0
3 years ago
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